x^3 - 2x^2 = 1

x^2 + 1 = 0
x^2 = -1

a.)
x^3 - 2(-1) = 1
x^3 + 2 = 1
x^3 = 1 - 2
x^3 = -1
x = -1

x = i^2
(x/i^2) = 1
-1 / -1 = 1

x^3 - 2i^2 = (x/i^2)
- 2i^2 = (x/i^2) - x^3
- 2 = (x/(i^2)/(i^2)) - (x^3/i^2)
- 2 = (x*(i^2)/(i^2)) - (x^3/i^2)
- 2 = (x*1) - (-1 / -1)
- 2 = -1 - 1
-2 = - 2

For x^3 - 2x^2 = 1 in this instance,
x^3 = -1
x^2 = -1
x = -1
i^2 = -1

b.)
x^3 - 2x^2 = 1
- 2x^2 = 1 - x^3
x^2 = (1/-2) - (x^3/-2)

x^2 = -1
-1 = (1/-2) - (x^3/-2)
-1 = (1/-2) - (-1/-2)
-1 = -1

x^3 = -1
-1 = -1/2 - 1/2
-1 = -1

x^3 = -1
x^2 = -1
x = -1

P.j.S

322 - Bones & Skulls_________x^3 - 2x^2 = 1
321=>231=> Gate 231
Enigma 23/17

Member No.: 32189 [P.j.S]
321 89
231 8+9
231 17
23117
23/17

Am I correct in those calculations Lord Spenser?

Attentively,
Enki

Did the enigma 23/17 come first? Or was is it calculated from 32189?

32189 could also be 3+2+1=6 + 8+9=17, 6+17=23, 2+3=5.
From the Child of Productivity 6-1=5. (read my signature).
Here I did not plan my number to be 5.

P.j.S

Good question! Actually it is hard to figure out.
Though, when one Googles Enigma 23/17
finds the following text:

http://en.wikipedia.org/wiki/23_Enigma
Discordianism

The Principia Discordia states that "All things happen in fives, or are divisible by or are multiples of five, or are somehow directly or indirectly appropritate to 5"[5]—this is referred to as the Law of Fives. The 23 Enigma is regarded as a corollary of this law. It can be seen in Robert Anton Wilson and Robert Shea's The Illuminatus! Trilogy (therein called the "23/17 phenomenon"), Wilson's Cosmic Trigger I: The Final Secret of the Illuminati (therein called "The Law of fives" and "The 23 Enigma"), Arthur Koestler's Challenge of Chance, as well as the Principia Discordia. In these works, 23 is considered lucky, unlucky, sinister, strange, or sacred to the goddess Eris or to the unholy gods of the Cthulhu Mythos.

As with most numerological claims, the enigma can be viewed as an example of apophenia, selection bias, and confirmation bias. In interviews, Wilson acknowledged the self-fulfilling nature of the enigma, implying that the real value of the Laws of Fives and Twenty-threes lies in their demonstration of the mind's power to perceive "truth" in nearly anything.

When you start looking for something you tend to find it. This wouldn't be like Simon Newcomb, the great astronomer, who wrote a mathematical proof that heavier than air flight was impossible and published it a day before the Wright brothers took off. I'm talking about people who found a pattern in nature and wrote several scientific articles and got it accepted by a large part of the scientific community before it was generally agreed that there was no such pattern, it was all just selective perception."[6]

In the Illuminatus! Trilogy, he expresses the same view: that one can find a numerological significance to anything, provided "sufficient cleverness."[7]

# [5] Principia Discordia, pg. 23
# [6] Robert Anton Wilson sees the clustering illusion everywhere, not just 23, Robert Anton Wilson Explains Everything (audiobook), December 2001.
# [7] Wilson, Robert Anton; Robert Shea (1984). The Illuminatus! Trilogy.

Our world has very specific structure. That is the matter.

The Fractal Universe may extend somehow over Time variable too.

Creative Pi : a perfect circle in time, (x y^7 z^2) / (x y^7(k/3)) = 3P,
x=4, y=7, z=360/7^3

A rational pi solution for a perfect circle in time with 2 dimensional calculations with spherical consequences in time. Invisible matter made up of micro b^n in 2 dimensional form are fractal of the larger circle in the Creative Pi Geometric Spencer Construction or 1080/7^3 circle with a radius of 0.5.

P.j.S

To conduct the message to mankind (if you want to), esp one related with the numbers 4 and 7 and 3 you should state the art ontologically in more clear form. I do understand quite well, but we are very few here who understand that.

3.14 has many specific whirls, esp on brain level.

hehehe
sometimes when i visit special places, i get to see those fractals infinitely...which brings me to ask why not infinitely pay more attention to how much can be used as a building block?

as theres ways to find out an infinite number of interpretation, thers ways to infinitely apply the interpretation.

It sounds correct but, e.g.:

there are such fractals called S-Attractors, they are never the same. Who knows, maybe in possibility of those 'interpretations' the Almightyness resides and Parallel Universes correlate via those 'interpretations' .

Look, what a number is? It is a symbol having shape, details whirls. E.g. look at number 6, what it says to you? Nothing? Now imagine that your brain suddenly gets an ability to see the full electromagnetic spectrum, not only the visible light. Who knows, maybe from that point of view the number 6 may start to look an object having some new Physical Properties as one e.g. attracting some kind of Electromagnetic Flow or discharging it, which shall be visible for you and was not visible before. The same way the Pentagram drawn on floor may start to look for you in quite different way.

So those things are not just building blocks. There is such an old 'non scientific' discipline called Amulet Magic, from its point of view the "Building Blocks" you mention are not the same.

A spherical universe uses a two dimensional circle to describe it in the Creative Pi Geometric Spencer Construction. Positive micro b^n are also much smaller 2 dimensional circles using the same principles of the rational pi in time as the universal sphere.

P.j.S

I want to remind you about ontology again, look:

The following terms you use must be well defined, as for side reader they are absolutely alien as you do not use conventional ontology, new things should be described by old ontology or by new ontology clarified in terms of old ontology or graphically:

1. spherical universe

Universe enclosed into a Sphere e.g. due to isotropic expansion after the Big Band?

2. How the Spherical Universe as is described in point 1 can use Two Dimensional Circle to describe the Two Dimensional Circle in the Creative Pi Geometric Spencer Construction?

For side reader it sounds a nonsense, right? Esp when you do not provide a link to the Creative Pi Geometric Spencer Construction as it is NEW TERM, am I right?

3. Please compare the following two sentences, in one I quote your one in the second I make some modification mentioned in bold:

"Positive micro b^n are also much smaller 2 dimensional circles using the same principles of the rational pi in time as the universal sphere."

"Positive micro b^n are also much smaller than 2 dimensional circles using the same principles of the rational pi in time as the universal sphere."

But it is just for more effective input into brain of a potential reader. Now

a) Positive micro b^n (it is absolutely new term, the one who did not read your comment about the black matter in LHC section http://brainmeta.com/forum/index.php?s=&sh...ndpost&p=103909 shall never venture to precept that phrase)

the rest of the sentence "also much smaller 2 dimensional circles using the same principles of the rational pi in time as the universal sphere" sounds like extraterrestrial message for ANY side reader.

To get what you write I must look at your previous definitions to try to get what exactly you mean even though I must accept that the exceptional ontology makes possible for me to get the very key idea you want to convey even at such a distance that separate us even without disclosure of true ontology you have in mind, Sir. But for the later part we cannot openly provide any criteria of truth if you want to convey the knowledge to a third party: the altar of knowledge remains closed for a third party.

Children, while reading this topic remember that the Matrix is just a Hollywood movie.

x^3 - 2x^2 = 1
x^3 = -1
-2x^2 = 1 - x^3
-2x^2 = 1 - -1
-2x^2 = 1 + 1
x^2 = 2/-2
x^2 = -1

x^3 = -1
x^2 = -1
x = -1

square root of x^2 = x. So square root of -1 = -1. Also,

x = sqrt -1 and -1. So sqrt -1 = -1.

The square root of -1 is -1.

P.j.S

A Study of x^3 - 2x^2 = 1 by PJS.

Ok, let me talk with you on other language: Who: http://www.intelligence.gov/1who.shtml

It is an excellent example:

12333

"The United States intelligence effort shall provide the President and the National Security Council with the necessary information on which to base decisions concerning the conduct and development of foreign, defense and economic policy, and the protection of United States national interests from foreign security threats. All departments and agencies shall cooperate fully to fulfill this goal."

Executive Order 12333

The departments and agencies cooperating to fulfill the goals of EO 12333 constitute the US Intelligence Community (the IC).

Nice joke is not it? ))))))))))))))))))))))))):

Executive Order Number 12333

NEO

and if rotate E clock wise we get W => NWO.

Btw, a nice example of S-Attractor logic.

Special Note: children, while reading this topic remember that the Matrix is just a Hollywood movie.

a.) i^2 = x^2
x^3 - 2x^2 = 1
x^3 - 2x^2 = i^2/x^2
-2x^2 = (i^2/x^2) - x^3
-2 = (i^2/x^2/x^2) - (x^3/x^2)
-2 = i^2 - x
make x = -1
-2 = -1 - -1
-2 = 0
0*-2 = 0*0
0 = 0

b.) i^2 = x^2
x^3 - 2x^2 = 1
x^3 - 2x^2 = i^2/x^2
-2x^2 = (i^2/x^2) - x^3
-2 = (i^2/x^2/x^2) - (x^3/x^2)
-2 = i^2 - x
make x = -1
-2 = -1 - -1
-2 = 0
-0 - 2 = -2
-2 = -2

x = -1
x^2 = -1
x^3 = -1

Problem: x^3/x^2 should equal x which is -1/-1 = 1. Instead it is -1/-1 = -1.
Is -1 = x^2 a mathematical lie? Does x^3 - 2x^2 = 1 prove that x^2 = -1 is a lie?
x^3 = -1 as shown before when x^2 = -1 making x = -1 as well.

c.) i^2 = x^2
x^3 - 2x^2 = 1
x^3 - 2x^2 = i^2/x^2
-2x^2 = (i^2/x^2) - x^3
-2 = (i^2/x^2/x^2) - (x^3/x^2)
-2 = i^2 - x
make x = 1
-2 = -1 - 1
-2 = -2

in this case.
x = 1
x^2 = -1
x^3 = 1

x^3 - 2x^2 = 1
1 + 2 = 1
1 = 1 - 2
1 = -1 x is not = to 1.

All Rights Reserved!
Peter Jeffrey Spencer

P.j.S

x^2 + 1 = 0
x^2 = -1

i^2 = -1,
(i^2)^3 = -1 = x^3,
x = -1

i^2/x^2 = 1

x^3 - 2x^2 = 1
x^3 - 2(-1) = 1
x^3 + 2 = 1
x^3 = 1 - 2
x^3 = -1

x^3 - 2x^2 = 1
-2x^2 = (i^2/x^2) - x^3
-2 = (i^2/x^2/x^2) - (x^3/x^2)
-2 = i^2 - x
1 = (i^2/-2) - (x/-2)
1 = 0.5 - -0.5

x/-2 = -0.5
x = 1 this is a contradiction from x^3 = -1,
x^3/x^2 = -1/-1 = x = 1, if x = 1 then x^3 equals 1 as well. However the equation shows that x^3 = -1
x therefore becomes -1 and 1 at the sametime proving that x^2 = -1 is a mathematical error.
If it were true then the Universe and everything in it would only be imagination. That is not true.

In the equation x^3 - 2x^2 = 1 it is shown that x = 1 and x = -1 exist in the value of x at the same time.

Since (x = 1) + (x = -1) = 0 then it becomes necessary to realize that zero (0) or the void has become present along with 1 and -1 at the same time so x^2 = -1 can exist as well. Therefore the binary logic in alternating from 1 to 0 to 1 in one second from a positive radius expanding to 0.5 of a second in every direction now creates a negative 1 identity. Counting from one edge of the universal diameter to the other now becomes like it is below, See?

1<---0--->1 is one universal edge to the other from a positive radius point of view 0.5 second of time.
-1<---0<---1 the x value of negative 1 is now present at the same time positive 1 is. So -1 + 1 = 0.
From 1 to -1 is one second long with 0 existing at the same time. Since this involves elapsed time for slower matter then the numberline becomes ...-3,-2,-1,0,1,2,3... as seconds or parts of seconds elapse.

The equation x^3 - 2x^2 = 1 proves this to be true. Simply said 0 which is near dimensionlessness is the center of the numberline speaking about the x axis presently as a universal diameter. -1 and 1 and 0 existing at the same time in the void.

Therefore the logic switching of 1 + -1 = 0 and 1 must be instantaneous for the void (0) to exist along with
x^2 + 1 = 0

x with a value proven to be 1 and -1 at the same time becomes x*x or 1*-1 or x^2 = -1. and
x + x = 0.

P.j.S

Thinking of the mathematical mind, having 1,0 and -1 together at the same time instantaneously, allows for reality and imagination both being present in a state of spiritual consciousness.

x^3 - 2x^2 = 1
x*x = x^2
x^2 = -1
x = (1,-1)
x+x = 0

x^3 - 2x^2 = 1
-2x^2 = 1 - x^3
x^2 = (1/-2) - (x^3/-2)
x^2 = -0.5 - (x^3/-2)
x^3 = -1
x^2 = -.05 - (-1/-2)
x^2 = -1

x, x^2 and x^3 all equal -1 at the same time.

sqrt x^2 = x
x = -1 in the negatively charged void.
x^3 = -1 the expression x^3 - 2x^2 = 1 is made complete.

x = the pair (1,-1) where
1 + -1 = 0
1 * -1 = x^2 equals -1
x+x=0, using the pair.
x*x=-1 where one x is given and the other is calculated.
if one x is +1 given as such in notation then the other could be calculated as -1 or vice-versa.
eg. 1*x=-1
x=-1/1
x=-1, positive 1 was given and the other calculated when 1x = x^2 = -1
Pairs like(1,-1) or (6,-6) or (8,-8) etc... may be channels or wormholes through time using x^2=-1.
This is where 2x=-1 and x^2=-1 converge perhaps in time. If a positive number is given in an equation then a negative counterpart may be at work in imaginery numbers to calculate a wormhole at some specific point in space.

Also 2x=-1 what is x?
x=-1/2
x+x = -1
-0.5 + -0.5 = -1 one negative second elapsed in the void. Compression of quantum forward time data back toward the origin of time.
2x = -1
x^2 = -1
2x/x^2 = 1
x^2 / 2x = 1
-1 is a channel through time or conventionally known as a wormhole in space.
(x^2/2x)=1=(2x/x^2) There needs to be parity involving all the math before the wormhole will open up in space. Where this is no parity a wormhole will not be present neither a leap in quantum time be made possible perhaps.

Theorectically speaking from a mathematical practise board in the Room of Objectivity.

All Rights Reserved!
Peter Jeffrey Spencer

"(x^2/2x)=1=(2x/x^2) There needs to be parity involving all the math before the wormhole will open up in space. Where this is no parity a wormhole will not be present neither a leap in quantum time be made possible perhaps."

The wormhole simply needs one pair of co-ordinates before the channel opens.
(-6,43) a point in time.

-6^2/2(-6) = 1 = 2(-6)/-6^2
-3 = 1 = -0.333...
-0.333... * -3 = 1 one end of the wormhole opens

43^2/2(43) = 1 = 2(43)/43^2
215 = 1 = 0.046511627
0.046511627 * 215 = 1 the other end of the wormhole opens. An error may mean a course correction in space flight. The quantum computer needs to keep all the decimals correct under very fast speeds of virus free computation for wormhole reciprocals to work right.

This wormhole example goes from quadrants containing -6 to 43 along the x axis. Something back in time is coming to the present. Like a memory at least.
-6------>0------------------------------------------->43 (x axis)

Where x is a multiple of -1 a wormhole may be forming to go backwards in time possibly.
sqrt x^2=x
x=-1=i
x=-1/i=1, x = 1 and x = i so...
i*x=x^2=-1
-1*1=x^2=-1

6*-1=-6 The memory that started on the x axis at -6 in the example, when it reached 43 it opened up to the conscious part of the brain from -6 the sub-conscious so to speak. Where x = (1,-1) at the same time as shown mathematically then imagination is present in the mind as well. One's thoughts filter back to the time of one's birth. A negative number may send a memory thought to the consious state along the x axis in which a straight line is the fastest time between two points. The mind may be useful in time travel perhaps if these mere mathematical speculations are correct.

Parity of 2x and x^2 both equaling -1 doesn't just start occurring now that this parity may have been discovered but has been occurring since the start of time in a physical condition. Infinite energy currently increasing in distance of one second in forward motion sends lesser forces of energy per second back toward the start of time or 0. Infinite energy keeping pace with exanding universal radius is in present time. A restart of energy to the present expansion with an elapse of one second sends what was real only a moment ago to memory in the conscious mind. Or everywhere that energy was a moment ago is now in a parsec of time and a real distance of elapsed time to go backward in time to.

These are relatively new terms in existence today. Only about the last 10 years or so from a labeling of term point of view. Athough conceptually in private for much longer than that. My terms do not eradicate E=mc^2 nor are they meant to. But they serve to complement E=mc^2 by introducing E=mc^2 Revised by PJS which is the manisfestation of maintained power and pure invisible energy slowing down to become visible matter. 2000 years from now Enki the terms associated with E=mc^2 Revised by PJS within the Theory of Space 0/0 Dynamics will not be as new or unfimiliar hopefully.

P.j.S

The quantum computer needs to run cool at absolute 0 or |0|. LHC may be a start of a quantum computer and time machine perhaps. Decimals oppose in the k atom or center of the pi time photon which maintains space normal temperature at about the point of freezing. The k atom is within the two dimensional shell of the photon. The k center would form an atomic shell but the opposing digits of pi keep k reduced to heating up without a shell. k is one of three atoms in the diameter of 1 infinity second in the pi time photon.

So the record of -0.326443795 would form 1/x = -3.063314561
-0.326443795 * -3.063314561 = 1.000000031 or minimum heat built up in the quantum computer
The first coordinate on the x axis is found. -3.063314561
The present time is then posted 0.235363442. 1/x = 4.248748198
(-3.063314561, 4.248748198) when added together they make a point found at 1.185433637 on the x axis. That is the case point. Then the memory can be viewed by extending into the y axis on a viewing screen from that case point on the x axis.

P.j.S

The pi time photon is theorized to exist at a temperature of about |0|. The heat from opposing the decimal strings of the first 27 digits of rational and irrational pi and continuing pairs of digits after that, is not stored in the photon. Rather a space normal temperature of about the freezing point is created everywhere the void is at 10! infinity resting or radius 0.5 second long.

The LHC at |0| and circular may be a much smaller version of the pi time photon. Opposing whole particles with their long decimal trail may be too advanced for the machinery and the know how of the people involved. Perhaps perfect sending a particle at maximum speed in one direction first. Just an idea.

P.j.S

A smaller collider circle is what maximum particle acceleration in one direction, may now, in the current collider afford learning about and be achieved, if ever. With a decimal string 27 digits long from 0 to maximum speed, then colliding (opposing digits) in a smaller, faster collider, it may afford the temperature to drop to |0| on its own at the center point or origin of the circle while the rest of the structure warms up to a temperature near freezing within the circumference of the new smaller collider.

The energy that was used to maintain |0| artificially for the collider could then be beneficially re-directed somewhere else while the collider was active.

It is not known what the two decimal string digits are. How can they be collided?

Then produce a particle from the source and time how long it is in that state before it reaches full speed in the collider. Count one unknown digit per second.
So a decimal string could be 60 digits because it took a minute to make a particle and accelerated it, to top speed. Then have two of these decimal strings in particle form and activate the colliding at the same time.

The two particles both alike should repel each other. Perhaps speed them up to the point that they stay in line but do not advance to touch each other. Then the collider would elapse the 60 seconds and the opposing digit strings would be consumed in holding the particle in place for the elapsing of the 60 seconds. Heat should be generated. The digit strings of the individual particles is a natural occurrence meaning that just because 60 was counted doesn't mean the string stops there.

So once the collider is in operation so that the particles merely face each other then maintaining that condition should continue to provide heat as long as the decimal strings continue to oppose each other, one pair of digits per opposing second, producing sustained heat in the collider with the right diameter to obtain practical heat with.

The problem is that they need to collide at the center point or origin point to make |0| sustained in the center point or k atom of the pi time photon. So other than that these collider efforts with not too great a diameter will or should create heat where the colliding is done. A smaller residential sized collider could possibly heat a house while a smaller collider than that may keep vegatables cool.

To accelerate 2 atomic shells in opposite direction so that they repell each other though in a close fixed collider stance, may allow oscillating the shells of the atoms (perhaps the atoms of iron could be tried) so that a potential difference with the lagging negative void could be generated. Then the collider could be a source of practical electricity and not just heat possibly.

P.j.S

From my signature:
x^2 + 1 = 0

x^3 - 2x^2 = 1
-2x^2 = (i^2/x^2) - x^3
-2 = (i^2/x^2/x^2) - (x^3/x^2)
1 = (i^2/-2) - (x/-2)
1 = 0.5 - -0.5
x/-2 = -0.5
x = 1 this is a contradiction from x^3 = -1,
x^3/x^2 = -1/-1 = x = 1, if x = 1 then x^3 equals 1 as well.
However the equation shows that x^3 = -1. x therefore becomes -1 and 1
at the same time proving that x^2 = -1 is a mathematical error.

To this:
x^2 = -1

x^3 - 2x^2 = 1
-2x^2 = (i^2/x^2) - x^3
-2 = (i^2/x^2/x^2) - (x^3/x^2), note: with x^3 = 1 here...
-2 = ((i^2*x^2)/x^2) - x, ...then x here = -1, with x^3=-1 then x=1.
-2 = i^2 - x
1 = i^2/-2 - x/-2
1 = -1/-2 - x/-2
1 = 0.5 - x/-2
0 = -1 + 0.5 - x/-2
x/-2 = -1 + 0.5
x = -2(-1) + -2(0.5)
x = 2 - 1
x = 1
With x^2=-1 then x=1 and -1 at the same time. To solve x=1 then x^3 needs to be -1 which solves for x as -1 as well. x^2 = -1 is in error. That seems to be the only answer.

from i problem:First post,
{I formulated an equation when averaging phi one time. It goes something like this:

x^3 - 2x^2 = 1; x^2 = -1

x^3 - 2(-1) = 1
x^3 + 2 = 1
x^3 = 1 - 2
x^3 = -1, True when x^2 = -1 consequently then x = -1 as well therefore...

-1 - 2(-1) = 1
-1 + 2 = 1
-1 = 1 - 2
-1 = -1; x, x^2 and x^3 all equal -1

Darren Lorent this is really interesting!

However when x = -1 alone then the equation goes like this:

x^3 - 2x^2 = 1
-1 - 2(1) = 1
-2 = 1 + 1
-2 = 2;
proving that x^2 = -1 cannot be true because x^3 = -1 is correct at the same time x = -1.

...yet now that I think about it maybe this will take the problem a little further...

-2 = 2
-2 -2 = x^2 = -1
-4 = x^2 = -1
-4*-1 = x^2 (edit, not -4/-1=x^2)
4 = x^2
sqrt 4 = x
2 = x; True when x^2 = -1 the same time as x^3 and x but now x also equals 2 why?

of course 2 = 2. the same as...
-2 = 2 = -1; x^2 = -1 as x and x^3 blend together
2 = x
-2 = x = -1
-2*-1 = x (edit, not -2/-1=x)
2 = x; test

x^3 - 2x^2 = 1
8 - 8 = 1 wow that was close! But perhaps salvageable yet...

0 = 1 is exactly my missing piece it seems. 0 means invisibility and 1 means one whole "an".
Invisibility needs a color apart from 0 the void. 0 green for go. Now I feel good about x^2 = -1 at the same time as x and x^3.

0/0 = 1 meaning relative 1 propelled! yeah!

Now in black 1/0=0 is established in my opinion. "an" / the void = the void.
The trigger to Action/Re:Action in Space 0/0.

(8-8)=1; (8-8)=0 is invisible with quantum memory 1 intact
8-8=0; 0 is the void with no memory left the same as (8-8)/0=0 which is 1/0=0;
also other normal mathematical rules for "0".

The Theory of Space 0/0 Dynamics

P.j.S}

With regard to x^3 - 2x^2 = 1 and -2 -2 = x^2 = -1 then 8-8=1 and 8-8=0 in binary changing times between 1 and 0 instananeously in the void. Invisiblibility meaning 0 for the void and also a^n = 1. 0/0= 0 or 1 in the void.

...yet now that I think about it maybe this will take the problem a little further...

-2 = 2
-2/2 = -1 = x^2 the same time that x and x^3 are -1. But...
-2 -2 = x^2 = -1
-4 = x^2 = -1
-4*-1 = x^2
4 = x^2
sqrt 4 = sqrt x^2
2 = x; True when x^2 = -1 the same time as x^3 and x but now x also equals 2 why? Explained above.

2x=-1 and x^2=-1 are reciprocals that equal 1. (2x=-1)/(x^2=-1)= 1 =(x^2=-1)/2x=-1).
Numerators change places instantaneously when 0 and 1 change states in the void.
When a^n - b^n - c^n = 0 and changes states fast enough so that c^n + b^n = a^n or 1 relative whole and are in existence with x^2=-1 instantaneously in the void all at the same quantum time.

A positive forward moving radius from the birth of time does not need 0 or -1. However with the creation of the void quickly between 0 and 1 the reversal of time allows for x^2=-1 and 2x=-1 so that 1,0 and -1 all can exist together and be purposeful.

P.j.S

-2 = 2
-2/2 = -1 = 2x the same time that x^2, x and x^3 are -1. But...
-1*2x=-1
-2x=-1
x=-2/-1
x=2

-2 = 2
-2-2 = 2x = -1
(-2-2)/2x = -1
-4/2x -1
-2/x=-1
-1x=-2
x=-2/-1
x=2

-2 = 2
-2/2 = x^2 = -1
-2 = 2x^2 = -1
-2*-1 = 2x^2
2 = 2x^2
2/2 = x^2
1 = x^2, note x^2 = -1 and 1 at the same time. Adding then together = 0. x^2 + x^2 = 0.

-2 = 2
-2 -2 = x^2 = -1
-4 = x^2 = -1
-4*-1 = x^2
4 = x^2
2 = x

Wnen x^2=-1 then x=2 with x^3-2x^2=1 is 8-8=1. Since 1 represents the numerator in 0/0 then it can be seen that x^2=-1 is travelling between 1"(0)" which is pure invisible infinite energy 8-8=1 and zero (0) the void 8-8=0, or 1 and 0 through time.

P.j.S

Just make sure and don't stick number 27 anywhere in your computation, or you'll never stop feeling the love from GOdALLMIGhitY, My child!

x^3 - 2x^2 = 9
-2x^2 + x^3 = 9
-2x^2 = 9 - x^3
-2 = (9/x^2) - (x^3/x^2)
-2 = 1 - x
-2 - 1 = -x
-3 = -x, multiply both sides by -1
x = 3

Code Buttons x^3 = 27.

P.j.S

The first 27 decimal places of phi and pi (rational & irrational) where infinity is resting at 10! at the edge of the spherical universe. Beyond this border the digits continue on endlessly representing an expandable universe with time and dimension present in the void. From a mathematical viewpoint.

P.j.S

Yea we knew that already! See:
http://brainmeta.com/forum/index.php?showtopic=20189

Watch out for lightening bolts! HE won't like it that you've exposed HIM!

x^3 -2x^2 = 1

x = -1,
-1^3 - 2x^2 = 1
-1 -2x^2 = 1
-2x^2 = 1+1
x^2 = 2/-2
x^2 = -1

x^2 = -1
x^3 -2(-1) = 1
x^3 +2 = 1
x^3 = 1 -2
x^3 = -1

x^3 = -1
-1 -2x^2 = 1
-2x^2 = 1+1
x^2 = 2/-2
x^2 = -1

x, x^2 and x^3 equal -1 at the same time.

P.j.S

http://www.cut-the-knot.org/fta/early.shtml

The last sentence of the article says it all.

http://www.cut-the-knot.org/fta/early.shtml

Reply to last sentence in the article: The equation x^3 - 2x^2 = 1

This equation has only been known for a few short years and Mr, Euler was no doubt not aware of it in his life time. Mathematicians are honest Hey Hey. Their work needs to stand despite subsequent discoveries if it is correct.

P.j.S

You really don't know much about human nature, do you?

http://www.bogvaerker.dk/Bookwright/axioms.html

However, it must be difficult to gain experience when stuck inside that padded cell.

LMA!!! I SMELL ROAST!
P.S. Welcome P.J.S. you seem like a pretty cool dude! WE just have a a form of say... initialte new forum members that talk lots shit as we try fix the Universe! LOL! This is the best science forum you'll ever find on the internet, I believe that wholeheartel

I agree that BrainMeta.com Forum is a great site.

We know that since x^2 + 1 = 0 and x = -1 that x^2 equals both +1 and -1.

x = -1
x^2 = 1 when the given is x^2 + 1 = 0 or simply x^2 = -1.

The sqrt x^2 = 1 is x = 1.

Now we know that x alao equals +1 and -1.

We can see from this that the imaginary number i^2 = -1 can be re-directed as x^2 = -1 instead of i^2 = -1. How?

x = +1, -1
x^2 = x*x
x^2 = +1 * -1
x*2 = -1
x^2 + 1 = 0

So long as the value of i*2 can be replaced then complex numbers need not be used in the construction industry. The value of -1 is still retained.

Could a bridge be built across the Avon River without using complex numbers but instead using the new quantity x^2 + 1 = 0 derived from the equation x^3 - 2x^2 = 1?

More importantly, who really cares about imaginary numbers anyhow The only time I have ever had to use them (quantum mechanics) is to give a real value to some made up shit i.e. Psi is probability amplitude and has no meaning, but psi^2* is probability density.

It is important to have the value of -1. Now x^2 + 1 = 0 can be retained as the quantity "x^2" = -1 instead of i^2.

This is because as made mention of already that the simple equation x^3 - 2x^2 = 1 has been found.

The sqrt x^2 = -1 is x = +1, -1. instead of i = sqrt -1.

x^2 = -1
x^4 = 1
x = 1, -1
sqrt x^2 = x

i^2 = -1
i^4 = 1
i = 1, -1
sqrt i^2 = i

i * i = 1 * -1
i^2 = -1
i = sqrt -1
i = 1, -1, sqrt -1

Consequently i = sqrt -1
i^2 = sqrt (-1 * -1) from sqrt 1 * -1 which is (sqrt -1 *-1 * -1)^2, 1 (sqrt -1)^2, 1 * -1 = -1
i^2 = -1
and
i^2 = sqrt 1 which is 1 (sqrt -1)^2, 1 (sqrt -1 * -1), 1 sqrt 1, 1 * 1 = 1
i^2 = 1

and so:

i^2 = 1 * -1
sqrt i^2 = sqrt 1 * -1
i = sqrt -1
sqrt -1 = sqrt -1 * -1 * -1, -1 sqrt -1, (-1 * 1) sqrt -1
sqrt -1 / sqrt -1 = (-1 * 1)
i / i = -1
i / i = i^2
i = i^2 * i
i = i^3 Wow! Remember 1 = 1^3
i = -1 * 1 * sqrt -1
i^3 = -1 sqrt -1
i^3 = (sqrt -1 * sqrt -1) sqrt -1
i^3 = i
(sqrt -1 * sqrt -1) sqrt -1 = sqrt -1
((sqrt -1 * sqrt -1) sqrt -1) / sqrt -1 = 1 * 1 * 1
i^3 = 1^3
i = sqrt -1 = 1
i^2 * i = i^3
-1 * 1 = -1
-1 = -1 * 1
i^3 = -1 * 1
i = -1 * 1

The solution for i = sqrt -1 could have been (-1 * 1) like x proves to be but then why the necessity of imaginary numbers like Flex says when you already have the quantity "x"?

Isn't a square root two similar values? Yes. The sqrt x^2 is x * x. But each x has a different value one positive and one negative.

x^2 = -1
x^4 = 1
x = 1, -1
sqrt x^2 = x
1 * -1 = -1
x * x = -1
x^2 + 1 = 0

Here the quantity x is squared allowing for positive and negative values each x. Novel.

P.j.S

sqrt -1 = 1
i = 1

x^3 - 2x^2 = 1

i = x^3 - 2x^2
i + 2x^2 = x^3
x^2 = -1
1 + 2(-1) = x^3
-1 = x^3
-1 = x
x + i = 0
-1 + 1 = 0
So...

x^2 + i^2 = 0
(-1)^2 + (sqrt -1)^2 = 0
1 + (-1) = 0
1 - 1 = 0 and...

x^2 + i^2 = 0
-1 + (1)^2 = 0
-1 + 1 = 0

P.j.S

Could you use this in an example solving real world problems?

Doing something like Integral (e^-ix)^2 dx

I would love too! Yet I know little calculus.

I'm 2 mentally inferior to fathom what is going on. Could someone please explain?

Without the Integral e^ix could be (e^1*-1)^2 or (e^-1)^2 now meaning (e^i^2)^2 or (e^x^2)^2 when
x^2 + 1 = 0 and (e^ix)^2 = (e^sqrt -1*1)^2 when x = 1 which would equal (e^1)^2 or just "e^2". That would be x = i circumstances or PJS Baker's Dozen found on MSN Groups archives.

I hope that this helps.

Previously it has been said that i^2 + 1 = 0 is a mathematical error. I believe that I just proved that sqrt -1 is equal to 1 among other things found.

In the equation x^3 - 2x^2 = 1 "i" is substituted for 1 leading possibly to new findings like Integral e^2 for example from x^2 + i^2 = 0. Possibly a new mathematical truth.

x = 1

x^3 - 2x^2 = i
1^3 - 2(1^2) = i
1 - 2 = i
i = -1

i + x = 0
-1 + 1 = 0

i = 1, -1

i * i = 1 * -1
i^2 = -1
i^2 + 1 = 0 It must be true!