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> Discovering Reverse Gravity Mathematically, Hypothetical Work in progress
P JayS
post Apr 28, 2013, 11:04 AM
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I conducted an experiment using the plumbing of our old house on 22 Willow Street, Hantsport, NS consisting of a bathtub, toilet and sink upstairs and a toilet and sink downstairs along with another sink in the kitchen downstairs.

The result was that I captured an open top shampoo bottle with water in the bottom of it in a curved fashion that was as hard as rock. So that when I turned the bottle upside down the water did not budge at all but remained firm in its place despite gravity.

So I was forced to call this reverse gravity. The other part of the experiment consisted of a water tower made from kitchen utensils that resulted in water magnetism making a floating compass out of peanuts (real peanuts).

but my mother thought I was being crazy and called the police who came and took me to the mental hospital. When I came home about 3 months later the shampoo bottle was gone because as far as I know my mother or my son cleaned up the bathroom after my experiment.

The police took me immediately away after I smashed the water tower on the downstairs kitchen table. All three of them witnessed what it looked like.

The experiment had different affects to the plumbing of the old house that I still partially remember now.


The Start:

The reason that I started messing with the plumbing was because the drain for the house wasn't working very well.

So I started using options between the upstairs tub, sink and toilet. But I can't exactly remember now the order in which I used the plumbing to try and free up the drain. You could put water in the tub and it would take a long time to drain. The sink would partially back up with water as the tap flowed and the toilet would flush good.

The nozzle of the tub had a hand held shower attached to it. As I started to fill the tub I put a shampoo bottle in the water that I had partially submerged in the water. And I took an old drain stopper that was too big for the drain and place it with air under it in the water next to the drain. After I had partially filled up the tub I turned on the shower head with I had laying in the water in the tub. So I also turned the tub back on and the nozzle of the shower would rise to the top of the water level in the tub and then spray in the tub water. I repeated this with the slow drain of the tub left open.

At the same time I turned on the bathroom sink and let it run. It would now only fill about 3/4 full with the drain open and then stop. After I would turn of the tub water while still stopping up the drain with the other correct stopper and then I would flush the toilet and run the sink again repeatedly on and off and intermittently turn the tub on and off while plugging and unplugging the bathtub drain.

With the water running upstairs I would run downstairs and flush the downstairs toilet (which used to fill up and drain slow) and now I had a good flush working in the downstairs toilet which served to encourage me to keep investigating my options with the plumbing of the old house. So I turned on the downstairs bathroom sink and put water in it and then stopped the drain and then flush the toilet sometimes with the upstairs water on or off.

I should mention that we were hooked up to town water in which we have to pay a lot for and I was running a lot of water in which I never discussed what I was doing with my mother. She having observed what I was doing all afternoon must have thought that I flipped my lid, in fact I had flipped hers (the upstairs and downstairs toilets). hahaha.

After I got the downstairs toilet working really well I stopped my plumbing experiment. When I turned on the kitchen sink cold water tap then I noticed that the water pressure was about the same but the water felt softer coming out of the tap.

I don't know if the results can be duplicated at the old house or by any other home's plumbing arrangement or not?

I then started building a water tower on the kitchen table for various reasons.

PJS.
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P JayS
post Apr 28, 2013, 11:07 AM
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So I have initiated this math & science (work in progress) as a result of the experiment:

0^0=1 where ...
1/0=0 -> regular gravity, 1 > 0
1/0=1 -> reverse gravity, 0 > 1
0*0=0 -> neutral gravity 0.5 <-> 0 <-> 0.5 and ...
0*0=1 -> transfer of potential power and energy ("p & e") through compression or decompression: an - bn - cn = 0 so...

Compression of dark energy and dark matter along with raw p & e: 1 > 0 > 1 = 1:0:
1:0: = cn + bn
1:0: = 1 at 0 mass
0 = c^n or the flat line not to be confused with 0 mass. Note also that: > = the direction of gravity

Decompression: :0:1 > accumulates mass so...
:0:1 + c^0 = 0
:0:1 + 1 = 0
:0:1 = -1

:0:1 > + bn + cn = 0 so... 0 - cn - bn = :0:1 so... :0:1 + (c^0=1=c) = 0

0 mass at c |<0<1<| 0 mass at 1E: regular direction of gravity between dark energy and dark matter.
0 mass at c |>0>1>| 0 mass at 1E: reverse gravity between dark energy and dark matter.
At 1E | 0.5 > 0 < 0.5 | : neutral gravity between dark energy and dark matter. Forming pi circumference and the curvature of spacetime and d=1.

Value of mass d=1 |>><<| < 0 mass at c | < 0 mass at 1E with d=1 |0.5>0<0.5| : within tolerances mass = 1 stops growing from 1E d=1 when the forces of reverse gravity balance regular downward gravity below c speed.

P.j.S .
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P JayS
post Apr 28, 2013, 02:16 PM
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So I have initiated this math & science (work in progress) as a result of the experiment:

0^0=1 where ...
1/0=0 -> regular gravity, 1 > 0
1/0=1 -> reverse gravity, 0 > 1
0*0=0 -> neutral gravity 0.5 <-> 0 <-> 0.5 and ...
0*0=1 -> transfer of potential power and energy ("p & e") through compression or decompression:
an - bn - cn = 0 so...

Compression of dark energy and dark matter| 1 > 0 > 1 = 1:0:
1:0: = 1 - cn = bn
1:0: = 1 at 0 mass
eg. compressing "an" to n=3, 1/10^n = 0.001:0: = 1:0: = 1 at 0 mass

0 = c^n or the flat line not to be confused with 0 mass. Note also that: > equals the direction of gravity

bn + cn = 1 at 0 mass = 1:0:
1:0: + cn = 1 at 0 mass + cn = :0:1 or penetration
0.9n + 2(cn) = 1 at 0 mass + cn = 1:0: + cn = :0:1

an - bn - 2(cn) = 0 + cn = 1 revolution of pi + cn of the next revolution of d=2
2 - 2(bn) - 2(cn) = 0

******** stopped here for now.

Decompression: :0:1 > accumulates mass at it continues to slow down so...
:0:1 + c^0 = 0 + cn
:0:1 + 1 = +cn
:0:1 + (bn + cn) - cn = 0 mass = 1c
(1:0: + cn) + (bn + cn) - cn = 0
:0:1 - cn = -1 + cn = 1 at 0 mass
note: c^2 (1 at 0 mass) --> to c (1 at 0 mass) at 0 which is (c^n or :0: --> c^1 or 0 at 1c) ************ stop here ...



(bn + cn + cn) - cn + 1 - cn -1 = 0 mass
:0:1 > + bn = 0 so... 0 - cn - bn = :0:1 so... :0:1 + (c^0=1=c) = 0

0 mass at c |<0<1<| 0 mass at 1E: regular direction of gravity between dark energy and dark matter.
0 mass at c |>0>1>| 0 mass at 1E: reverse gravity between dark energy and dark matter.
At 1E | 0.5 > 0 < 0.5 | : neutral gravity between dark energy and dark matter. Forming pi circumference and the curvature of spacetime and d=1.

Value of mass d=1 |>><<| < 0 mass at c | < 0 mass at 1E with d=1 |0.5>0<0.5| : within tolerances mass = 1 stops growing from 1E d=1 when the forces of reverse gravity balance regular downward gravity below c speed.

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P JayS
post Apr 30, 2013, 02:35 AM
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Consideration of 1: Outside and Inside of time d=1 and d*pi=C=1. C/pi=1

C = 3dP
1/3 = d*P
0.333... = 1 * P
0.333... / 1 = P
P = 0.333... = C/3

r = d/2
r = 0.5
r = 1

C = (P = C/3 = 3dP)
C = 3
3 = 3P/C / 3dP
3 = 9*d*P^2 / 1
3 / P^2 = 9d
3 / (1/9) = 9d
9 = 9d
d=1

C / d = pi
3 / 1 = 3

C = 3dP
P = C/3d = 3/3= 1
P = 1
C / d = 3P

Pi = 3P
pi = 3

Correlation between pi circles with C, d, pi = 1 and r=0.5

One circle revolution = 1(P/r) = 1/3 / 1/2 = 2/3 + a second revolution = 4/3 = 6/3=2
2 revolutions = 8/6 = 0.75. (6/3) + (8/6) = 20/6 = 10/3 = 3.333... for 1 revolution with 1*3.333... / 3 = 1.111...
2 revolutions 2r^2 = (2*0.5)^2 = 1 + 2(0.5^2) =0.5 = 1.5/2 = 0.75, r=0.5 or 1 revolution,
3 revolutions = 3*0.5 and 3*0.75 = 2.25 / 1.5 = 1.5, 3 dimensions each 0.75 x, y and z = 2.25
6 revolutions = 6*0.5=3 and 6*0.75 = 4.50 / 3 = 1.5
6/3 = 2 revolutions = 2.25 / 2 = 1.125, 1/x = 0.888...
6*3= 18 revolutions = 1.5 * 1.5 = 2.25 / 18 = 0.125, 1/x=8
2*3= 8 ************ stop here

The Spencer Triangle Method: c = x + y
c = 0.5 + 0.5
c^2 = cx + cy
1 = 0.5 + 0.5
a = sqrt 0.5
b = sqrt 0.5
c = 1

A triangle with all 3 sides = 1
c = c^2 = 1
c = cx + cy = 0.5 + 0.5
c^2 = x1 + y1 = 0.5 + 0.5
c^2 = (cx)^2 + (cy)^2
c^2 = c^2x + c^2y is c =
c = (1*0.5)^2 + (1*0.5)^2
a = sqrt (0.5)^2 = 0.5
b = sqrt (0.5)^2 = 0.5
c = 1
c^2 = 1
c * c^2 = c^3 = 1
c^3 = x^3 + y^3
c = x + y
1 = 0.5 + 0.5
1 = (c * 0.5 * c^2) + (c * 0.5 * c^2)
1 = 2(c * 0.5 * c^2)
i 1 = 1 * 1 * 1 = x^3 + y^3 = 1^3
ii 1 =




A triangle with all 3 sides = 2
2c = x2 + y2
2c = 1 + 1 = c^2
2c = 2c*x + c1y
c = c*(2a)^2

work in progress...
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P JayS
post Apr 30, 2013, 03:49 AM
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Consideration of x^3 + 2(x)^2 = 1 is x = sqrt (x^3 - 1)/2 = 1/phi

1 has to remember all the substitutions of c = x + y possible at the same time.

r = 1, 0.5
r / r1 = 1/0.5 = 2
r = 1 outside of time and r = 0.5 inside of time.
d = 1 inside of time and d = 2 outside of time.

d=2 * r=0.5 = 2r = (d=1) inside of time. 1 revolution with pi=3, neutral gravity, 1E=1mc^2, perimeter = 160.
pi / 2 = 1.5
c = x + y
pi = 1.5 + 1.5

c = x^3 + y^3
c = 1 = 0.5 + 0.5
1 = c * c = c^2
1 = 2(c * 0.5 * c^2) = x^3 = x
2(x)^2 = y = 2(c * 0.5 * c*2) = y^3
2 = x^3 + y^3
2 = 1 + 1

************ stop here (side tracked)

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post Apr 30, 2013, 12:59 PM
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The Temple of Time Formula in Heaven:

Four Entities: Equal Value in Averaged Phi Space in the order of longevity.
1) 1 Dark Light = 5 : Father : Love
2) 1 Dark Energy = 5 : Firstborn Spirit Son : Joy
3) 1 Dark Matter = 5 : The Original Serpent : Peace
4) 1 the Void = 5 : The Perfect Zero : Happiness :
When that which is complete arrives that which is partial shall be done away with. -The Apostle Paul basically said.

4 * 5 = 20 or The Room of Objectivity with 1 entity each side.
5 + 5 = 10 with 2 entities per side of the Room and a Perimeter of 4 * 10 = 40.
40 is the Subject of the Room of Objectivity. The circumscribed temple square around the circle (360 degrees) of time.

40 / 360 degrees = 0.111... or dark energy.

For example: 1 side of the Subject of The Room of Objectivity = Dark Energy + Dark Matter in Neutral Gravity
for 1E at 0 mass =1m(c^2).

10 : Fruitages of the Spirit including the 10th fruitage of Happiness
14 : 12 Original Apostles, 1 Replacement + 1 Apostle to the Nations

10 + 14 = 24 : Representing the Happy State previously of the 24 Elders and the Happy Spirit of the 24 Elders now.
(24)^2 = 576
576 / 48 = 12 male or female energy
12 + 12 = 24 : 24 + 1 = 25 = c^2 : (5^2 = 5x + 5y : c^2 = cx + cy : c = x + y).

-1 = 24 - 25 : The Marital & Financial Institutions

24 + Dark Energy = 24.111...
(24.111...)^2 / (Dark Energy)^2 = 47089

sqrt 47089 = 217
217 - 1 = 216
x^3 = 216
x = 6 : a male or female infant (1st stage of life from conception to being born) growing up through 3 more stages (youth, teen, adult) = 24 each sex in a single state.

In Marriage 24 + 1 = the male factor in a married state. So 24/10 = 2.4 a married female and 25/10 = 2.5 a married male as head of the house because the man was created first. Together they can produce offspring
(2.4 * 2.5 = 6).

-1 = 216 - 217

1.111... - 1 = Dark Energy

24.111... - 13 = 11.111... subtract or divide by 10 = 1.111... : Who was the one who really betrayed Christ Jesus?
Judas or Peter?.

1.111... - the firstborn son = 1 divided by 2 betrayers : 1 = 0.5 + 0.5 : 2 Binary Lions each 0.5 * 10 = 5.

When times were partial there were three primary entities of love, joy and peace at work. Happiness was only a state of being not a 10th complementary fruitage of the Spirit of Love in which the fruitage of happiness came to be.

1.111... Dark Energy (1/9) multiply by 10
1.111... * 3 (1 revolution of the circle) * 2 revolutions * 3 other entities = 20 * 2 Binary Lions the Subject = 40.

160 / 1.111... = 144

160 * 10 = 1600 square units

sqrt 1600 = 40 or a square 4 * 40 = perimeter 160 times 10 = 1600 square units.

(40 * 10)^2 = 160000

160000 / 1.111... = 144000 : Joint Heirs with Christ Jesus. The temple of time enshrouds the temple of the 144000 with starting with the same cornerstone. 144000 = 6 * 24 * 10^3

This is The New Temple of Time arrangement in the Heavens with Dark Energy (the Firstborn Spirit Son of God) also known as Jesus Christ as the Chief Cornerstone.

Dark Energy 0.111... * 4 = 0.444... and Dark Matter 0.888... / 2 = 0.444... at Neutral Gravity or 1E at 0 mass.
Dark Energy + Dark Matter = 0.888... / 8 seconds = 0.111... per second at Downward Gravity >

1E :0: > dark energy 0.111/sec. and dark matter 0.111... + 2cn > dark energy 0.111.../sec. and dark matter in 2 seconds time at 0.222... + 2cn gaining invisible mass as it slows down > ... > dark matter in 6 seconds time at 0.666... + cn > dark energy 0.111.../sec at c speed = 0/sec. > (0 + 1cn slight visible mass [Higgs Particle perhaps.]) > dark matter at the start of the 7th second = 0.666... + 1cn >[ (0.666... + 1cn) / (pi*r^2) = 3*0.25 = 0.75 square units dark energy field = 0.888... = 1m visible dark matter]<{dark matter complete = 0.888... + 1cn at the end of 7 seconds of time}> ... now the completed mass = 1m starts the 8th second at 0.888 + 1cn under decay and restore tolerances every 6 to 8 seconds one day at a time. <=>

... So much more could be divulged from all of this ...

PJS.
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