Stanard vs Metric Operating Systems, Observations leading where? ... Who knows? ... 
Stanard vs Metric Operating Systems, Observations leading where? ... Who knows? ... 
P JayS 
Apr 25, 2013, 07:28 PM
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#1

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
The Title should be Standard vs Metric Operating Systems.
10! = 3628800. If these are miles then 10! / 0.6 = 6048000 km If these are km then 10! * 0.6 = 2177280 miles 2177280 miles divide the diameter of Creative Pi = 1152480 = 1.8P. 1.8 = x from the hypotenuse of a 3, 4, 5 triangle c = x + y. P = 360/7^3. so 10! km / 3P = 1152480 miles "d". so dxP = (10! km * 0.6) = 2177280 miles 2177280 miles / 3P = 691488 miles / 0.6 = 1152480 kms hmmm... what is going on here? 10! km * 0.6 = 2177280 miles / x*P = 1152480 miles * 3P = 10! miles. C = 10! km equals C = 10! miles. 10! km / 3P = 1152480 km 10! miles / 3P = 1152480 miles 10! km / 3P = 1152480 miles 1152480 miles = 1152480 km in the circumference with a diameter of 1 and C = 3dP or x / 0.6 = 3 times d*P. Does anyone have any comments?. 
P JayS 
Apr 25, 2013, 09:27 PM
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#2

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
10! km * 0.6 = 2177280 miles / 3P / 0.6 = 1152480 km
2177280 miles / x=1.8 / P=360/7^3 = 1152480 miles 10! km / 3P = 1152480 km or miles. d = 1152480 km C = 10! = d km * 0.6 = 691480 miles * 3P = 2177280 miles / 0.6 = 10! miles or km d = 1152480 miles C = 10! = (d miles * x * P) / 0.6 = 10! km or miles C = 3dP C = 10! km or miles / 3P = d (miles or km) = a diameter of 1 second where 1152480 miles = 1152480 km in time. C = 10! km or miles / pi = d (miles or km) = a diameter of 2 seconds where d miles = d km in time. C = 10! / (Pi=3P) is (d irrational pi) = (d rational pi) in miles or km in time. Irrational pi is like a smaller measured pi circumference (standard) that fills the same space as a larger measured rational pi circumference (metric) where 1 yard = 1 meter in time. This is the same as C/d= 3 where d and P both = 1. This is where the arc of the circle subtending the radius of the inscribed hexagon are the same distance in time. So the diameter and the radius both = 1 at the same time. Mind boggling! C / pi = d = 1 is Pi of the Bible, C / 3P = d = 1 is Creative Pi and C / pi = 2r = d = 1 is Transcendental Pi. All have the same unmeasured circumference of 10! in time and all three occupy the same space in averaged phi conditions. C = 10! / TP = 1155082.915... "TP" is transcendental pi = 3.141592654..., Blended E=mc^2. c is measured scientifically. C = 10! / CP = 1152480 "CP" is creative pi = 3P, P = 360/7^3, c^7=7.77e+36. c is mathematically calculated. C = 10! / BP = 1209600 "BP" is pi of the Bible = 3, c^n = 0. This is the ability to be everywhere at the same time in space. c^0 = 1 c^n = 0 The subtraction law an  bn  cn = 0 now takes on the characteristics of c^0  bn  cn = c^n or both as 1  0.999...  1/10^n = 0. Darklight  (Invisible Dark Energy + Invisible Dark Matter)  energized time = The Void c^0  (0.111... + 0.888...)  1/10^n compressed to 1:0: = c^n = :0:1 => i^2 dimension. an  bn  cn = 0 Now Science has estimated that invisible dark matter is a ratio of 6 to 1 for visible mass in the universe. Since visible mass originates with dark energy then this makes visible matter 6 * (1/9) = 0.666... It is interesting to note that invisible dark matter / visible matter is the inverse of one side of the concentric square of the Creative Pi Geometric Spencer Construction. 0.888... / 0.666... = 1/0.75. The result is still greater than 1 because the invisible dark matter is travelling faster than the flat line (c^n=0) of c speed which represents 0 visible mass. Once 0 or the flat line has been breached then the accumulation of mass is the work of dark energy again. This time 0.75 = 0.666... / 0.888... or one side of the concentric square acting upon new mass slower than c. (0.75)^2 + (0.75)^2 = 1.125 which is the inverse of invisible dark matter. It is interesting to see the relationship of the concentric square of dark energy with the binary lion associate of invisible dark matter which is the inscribed hexagon. Each have a perimeter of 3. So 0.333... of dark energy + 0.333... of invisible dark matter each result in the sum of 0.666... or visible matter below c speed. Thus we have Love (the circumference and darklight) and Joy (the concentric square and dark energy) and Peace (the inscribed hexagon and dark matter) making up 3 entities or each 1/3 of the heavens or arc of the circumference in averaged phi space. When Peace left Heaven he took 1/3 of the stars with him. Love + Joy + Peace = 0.333... + 0.333... + 0.333... = 0.999... When Peace left 0.999...  0.333... = 0.666... in a chaotic state. In other words visible matter 0.666... in the universe has been in an observed chaotic state within averaged phi space. Averaged phi space is a circumstance where God has permitted other entities to be equal to him in a quest to find a Happy Spirit to complete and complement the spiritual estate of God. This has been a quest for the Perfect Zero in order to find a suitable marriage mate for ONE "1". Thus 1 & 0 make 10 (ten) or binary language as well for example. Ten factorial is not 0123456789. It is 123456789&10. Much can be said about all of this... But this is getting more into the Spirituality of math & science from my own personal opinion which I have not been strenuously developing in the Binary Legal Language of Love since the "." that I have developed lately has come to be recognized by those in heavenly places. My bazaar writing days (which were necessary to get the binary legal language of love up and running) seem to be over now. Rest assured though that Mankind has its own set of Scales now in the Justice System of God and God is being weighed upon them for several reasons currently. 
P JayS 
Apr 25, 2013, 10:27 PM
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#3

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
Perhaps we should look at the circumference instead.
C = 3dP C = (xdP) / 0.6 d = 1152480 miles C = 1152480 miles / 0.6 = 1920800 km times (x=1.8) = 3457440 km times (P) = 10! km d = 1152480 miles C = 3dP = d * 3P = 1152480 miles * (1080/7^3) = 10! miles d = 1152480 km C = 3dP = d * 3P = 1152480 km * (1080/7^3) = 10! km It seems to be the inscribed hexagon where the two values merge. d = 1152480 miles times 3 = 3457440 miles times (P) = 10! d = 1152480 miles / 0.6 = 1920800 km times (x=1.8) = 3457440 km times (P) = 10! C = 10! is absolute despite the measuring system or the value of pi. Therefore the radius and diameter are absolute as well. d = C/3P = 1152480 for a circumference with a 1 second diameter r = C/6P = 576240 d = C/pi = 1155082.915 for a circumference with a 2 second diameter r = C/(2pi) = 577541.4575 A single circumference = 10! with a rational pi for a 1 second diameter and an irrational pi with a 2 second diameter involves great secrets of order and chaos within the time keeping of the living and breathing universe. P.j.S . 
P JayS 
Apr 25, 2013, 11:39 PM
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#4

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
In calculating quick tolerances in time it can be seen how a hypothetical pi could come in handy.
H pi = sqrt (pi * 3P) = 3.145138349... Creative Pi / 1.00112863... = H Pi and Transcendental Pi * 1.00112863... = H Pi H pi creates a flat line (c^n=0) for the zero dimension between the breathing and exhaling of penetration and exhaust of dark energy and invisible dark matter inside of lesser than zero space where all the visible dark matter collects. This also creates a flat line between measured rational pi and irrational pi space. H Pi on the flat line is the split of the measured diameter values d=1 and d=2 of rational and irrational pi circumferences each only 1 second long in duration. The split is sqrt (1 * 2) = sqrt 2 or a diagonal of the circumscribed square around the H Pi circumference with a diameter of 1 in the simple line of time. The diagonal sqrt 2 and the diameter 1 both are 1 second long in duration. What we find is that visible matter 0.666... is inside of space of the infinity second of sqrt 2. Therefore invisible dark matter outside of the time and space of the simple line of sqrt 2 is 0.888... / 0.666... = 1/0.75 = 1.333... So invisible dark matter within the space of the circumscribed square of time becomes 1.333...  1 second = 0.333... or 1/3 of the H Pi circumference along with dark energy and darklight which are already each 0.333... of the circle of life in averaged phi space. Therefore exhaust expels into greater than 1 second diameter space and penetration comes from greater than 1 second diameter space. But less than sqrt 2 space of the circumscribed square which is still 1 second in duration. It can now be seen that the Creative Pi circumference which measures greater than or consumes more space than H pi, captures invisible dark matter black hole exhaust, in greater than zero space and the circumference of Transcendental Pi which is smaller than H pi space, absorbs dark energy penetration in lesser than zero space. It can also be seen that the massless photon cannot rest on the flat line of H Pi. Therefore compression of dark energy at 1:0: will spill over into the dividing of the void and the producing of visible matter. The tendency is for the massless photon to resist taking on mass. But as seen by successful penetration of the zero dimension that this is not impossible. The tolerances of the circumference of Transcendental Pi houses all the visible matter in the i^2 dimension. In time deep space will warm up to just about the freezing point or a little warmer in places with breathable air but the temperature cannot rest on the flat line of zero degrees since the entire universal system must either expand or contract as the case may be. The body temperature of the capacity of visible matter other than the gamma ray bursts from black hole activity will also help warm space up in time. 
LoFi Version  Time is now: 22nd November 2017  06:49 AM 