Pi of the Bible and 9!, Nine Factorial 
Pi of the Bible and 9!, Nine Factorial 
P JayS 
Oct 01, 2012, 02:39 AM
Post
#1

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
x^4 / x^3 = 1/1 = 3/3 = 81/27 = 3 = x
x^3 + x^2 + x = 39 + x^4 = 120 x + 1 = 4 x^2 + 1 = 10 x^3 + 1 = 28 which is 4 * 7^1 39 + 1 = 40 which is 4 * 10 120x = 360 which is pi=3 120 + 1 = 11^2 = (x^2 + 2)^2 36x / x^4 = 36 x=1 36x / x^4 = 1.333... x=3 36x / x^4 = P/10 x=7^1 40 * 7^7 = 32941720 32941720 * P/10 = 3457440 which is the perimeter of the circumference and the concentric square and the inscribed hexagon labelled (per). 9! / (P/10) = 3457440 / 6 = 576240 radius 2r * 3 = 3457440 Pi = 3 The Molten Sea mentioned in the Bible had a radius of 5 cubits. The circumference was 6 times the radius around = 30 cubits. This resulted in a diameter of 10 cubits and a pi of 30/10= 3. This is based on a circle and hexagon with a perimeter of 3457440 / 6 = 576240 radius. 3457440 / 2r = 3 At this time 10 is not used. P/10 is not P. I simply label the decimal P/10 that occurs naturally from 252 / 2401. i don't think that P was invented with 9!. Therefore a circle was C = 3d not C = 3dP. P/10 * 10 = P This brings 10 into the count and makes 10! instead of 9!. 3457440 * P = 10! 3457440 / P = 4 * 7^7 10! therfore equals 4 * 7^7 * P^2 10! / 3P = 2r = 1152480 / 2 = 576240 radius. The same radius as 9!. In 2D (two dimensions) the arc of the circle is longer than the radius of the subtended line. The arc = r * P = 0.5 * P = pi / 6 = 0.524781341... 6r = the perimeter of the inscribed hexagon 6r * P = the circumference of the circle at 10! using base 10. 120 * pi=3 = 360 360 / (P/10) = 3430 3430 / 7^3 = 10 360 / 7^3 = P in base 10. 
P JayS 
Dec 31, 2012, 01:33 AM
Post
#2

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
x^4 + x^3 = 108
108 / x = 36 36 x / x^4 = 36 then x = 1 36 x / x^4 = P/10 then x = 7 9! / (P/10) = 3457440 which is the perimeter of the inscribed hexagon from the Creative Pi Geometric Spencer Construction. 3457440 / 6 = the side of the radius = 576240 2 times the radius = 1152380 which is the diameter. 3457440 / 1152480 = 3 the perimeter of the inscrbed hexagon divide the diameter = a pi of 3. All that is proved is that the perimeter of the inscribed hexagon is 3 when the diameter is 1. However P/10 times 10 = P 3457440 * P = 10! 10! makes a perfect circumference. C / d = 3P C = 3dP 36x / x^4 = P/10 10(36x) / x^4 = P x = 7 2520 / 2401 = P P = z C = (x y^7 z^2) = 10!, x=4, y=7 and z=360/7^3 C / z = the perimeter of the inscribed hexagon = 3457440 divide 3 = the diameter 1152480 divide 2 = the radius 576240 Pi = 3628800 / 1152480 = 1080 / 7^3 = 3P which is Creative Pi or rational pi. P = The arc of the circle which subtends the radius is longer than the radius. r = 1 P = 360/7^3 3P = pi circumference = 1080 / 7^3 
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