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> Pi of the Bible and 9!, Nine Factorial
P JayS
post Oct 01, 2012, 02:39 AM
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x^4 / x^3 = 1/1 = 3/3 = 81/27 = 3 = x

x^3 + x^2 + x = 39 + x^4 = 120

x + 1 = 4
x^2 + 1 = 10
x^3 + 1 = 28 which is 4 * 7^1
39 + 1 = 40 which is 4 * 10
120x = 360 which is pi=3
120 + 1 = 11^2 = (x^2 + 2)^2

36x / x^4 = 36 x=1
36x / x^4 = 1.333... x=3
36x / x^4 = P/10 x=7^1


40 * 7^7 = 32941720
32941720 * P/10 = 3457440 which is the perimeter of the circumference and the concentric square and the inscribed hexagon labelled (per).

9! / (P/10) = 3457440 / 6 = 576240 radius
2r * 3 = 3457440
Pi = 3

The Molten Sea mentioned in the Bible had a radius of 5 cubits. The circumference was 6 times the radius around = 30 cubits. This resulted in a diameter of 10 cubits and a pi of 30/10= 3.

This is based on a circle and hexagon with a perimeter of 3457440 / 6 = 576240 radius.
3457440 / 2r = 3

At this time 10 is not used. P/10 is not P. I simply label the decimal P/10 that occurs naturally from 252 / 2401.
i don't think that P was invented with 9!. Therefore a circle was C = 3d not C = 3dP.

P/10 * 10 = P

This brings 10 into the count and makes 10! instead of 9!.

3457440 * P = 10!
3457440 / P = 4 * 7^7

10! therfore equals 4 * 7^7 * P^2

10! / 3P = 2r = 1152480 / 2 = 576240 radius. The same radius as 9!.

In 2D (two dimensions) the arc of the circle is longer than the radius of the subtended line. The arc = r * P = 0.5 * P = pi / 6 = 0.524781341...
6r = the perimeter of the inscribed hexagon
6r * P = the circumference of the circle at 10! using base 10.

120 * pi=3 = 360
360 / (P/10) = 3430
3430 / 7^3 = 10
360 / 7^3 = P in base 10.
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P JayS
post Dec 31, 2012, 01:33 AM
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x^4 + x^3 = 108
108 / x = 36

36 x / x^4 = 36 then x = 1
36 x / x^4 = P/10 then x = 7

9! / (P/10) = 3457440 which is the perimeter of the inscribed hexagon from the Creative Pi Geometric Spencer Construction.

3457440 / 6 = the side of the radius = 576240
2 times the radius = 1152380 which is the diameter.
3457440 / 1152480 = 3 the perimeter of the inscrbed hexagon divide the diameter = a pi of 3.
All that is proved is that the perimeter of the inscribed hexagon is 3 when the diameter is 1.

However P/10 times 10 = P
3457440 * P = 10!
10! makes a perfect circumference.
C / d = 3P
C = 3dP

36x / x^4 = P/10
10(36x) / x^4 = P
x = 7
2520 / 2401 = P
P = z

C = (x y^7 z^2) = 10!, x=4, y=7 and z=360/7^3

C / z = the perimeter of the inscribed hexagon = 3457440
divide 3 = the diameter 1152480
divide 2 = the radius 576240

Pi = 3628800 / 1152480 = 1080 / 7^3 = 3P which is Creative Pi or rational pi.

P = The arc of the circle which subtends the radius is longer than the radius.
r = 1
P = 360/7^3
3P = pi circumference = 1080 / 7^3
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