Creative Pi, The tangible rational pi solution for the invisible point 
Creative Pi, The tangible rational pi solution for the invisible point 
P JayS 
Sep 13, 2012, 05:05 AM
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#1

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
Creative Pi & The Child of Productivity! Creative Pi & The Child of Productivity! Download Media Export to Blogger Export to Tumblr Group Settings Customize Site Media Locker View Members (3) Invite Members Moderation Delete Group Report Abuse Home Notes Blog Creative Pi Geometric Spencer Construction Oct 20, '10 3:41 PM by P. Jeffrey for everyone school0pjs1 The circumference is 10 factorial. C is (x y^7 z^2) or 3628800. Only the circumference is known in C/d=pi. (x y^7 z^2) / (x y^7(k/3)) = 3P. x =4, y=7 and z = 360/7^3. Now divide C (3628800) by the factor z (360/7^3) and we get the perimeter of the concentric square (3457440) in the construction. This perimeter is the same as the inscribed hexagon. The radius is the same as one side of the inscribed hexagon. Divide the perimeter of the inscribed hexagon by 6 and the value of the radius is known as 576240. There is another way to find the value of the radius. Find the value of the hypotenuse in the triangle with the radius as the hypotenuse. Triangle UOB. Now two times the radius equals the diameter or 1152480. C/d=pi. 3628800/1152480=(1080/7^3) = 3P or 3.1486880466472303206997084548105... or rational pi. From the School of P.j.S Original Mathematics & Related Sciences: Creative Pi Owned by: Peter Jeffrey Spencer All rights reserved! reply edit delete 15 CommentsChronologicalReverseThreaded school0pjs1 wrote on Oct 21, '10, edited on Oct 23, '10 Creative Pi Abstract Algebraic Equation: (x y^7 z^2) / (x y^7 (k/3)) = 3P, C=10 factorial. C/d=pi. x y^7 cancels leaving z^2 / (k/3) = 3P 3 z^2 / k = 3P 3 z^2 / 3k = P z^2 / k = P z^2 = kP z = sqrt kP 360/7^3 = sqrt (360/7^3) * (360/7^3) 360/7^3 = 360/7^3 z = k = P = 3(360)/7^3 = 1080/7^3 rational pi = 3P = pi. All rights reserved! school0pjs1 wrote on Oct 23, '10, edited on Oct 23, '10 Abstract Algebra for pi: Pi is between 3 and 4. "P" is (the length of the arc subtending the radius divide the radius). Or 3 times the diameter times P = a pi circumference of 3P when the diameter = 1. So pi = 3P. C = 3 d P C/d=3P C/d=pi. Pi = 3P. The circumference (x y^7 z^2) / 3P = the diameter. Since 3P does not have x y^7 in it we know that it must cancel in the diameter. But because 3P is bigger than 3 we know that there is a little piece of the diameter left over. I call that "k" and divide it by 3. The diameter then is (x y^7(k/3)) The Creative Pi Abstract Algebraic Equation: (x y^7 z^2) / (x y^7(k/3)) = 3P or C/d=pi given that C = 10!, x=4, y=7 and z =360/7^3. Then dividing the 10 factorial circumference by the factor "z" the 576240 radius shows up in the geometry. Two times the radius is the diameter 1152480. The circumference 3628800 divide the diameter 1152480 = pi. The circumference is known in the algebra but the diameter and pi are not known due to "k" and "P" respectively. All rights reserved! school0pjs1 wrote on Oct 23, '10 3P or 3(360/7^3) = pi = 1080/7^3 has not yet been proven false! All rights reserved! school0pjs1 wrote on Nov 2, '10, edited on Nov 2, '10 C= 3dP A circumference equals 3 times the diameter times "P" or the subtended radius by the arc of a circle covering the radius. C / d = 3P or pi. 10! / 1152480 = 3(360/7^3) school0pjs1 wrote on Nov 4, '10 z = sqrt kP 360/7^3 = sqrt 360/7^3 * 360/7^3 This is the only solution where C of C/d=pi is the only given and k and P of the diameter and pi are solved at the same time. 360/7^3 = 360/7^3 z = k = P school0pjs1 wrote on Nov 9, '10 For example 22/7=pi assigns given values to both the circumference and the diameter for a rational pi solution for C/d=pi. However Creative Pi assigns a value to the circumference only and solves for the rest. The value of the circumference is 10 factorial or 3628800. Thus (x y^7 z^2) / (x y^7(k/3)) = 3P is really C/d=pi. Pi = 3P. school0pjs1 wrote on Nov 18, '10 Together the Creative Pi Geometric Spencer Construction and the Creative Pi Abstract Algebraic Equation prove that there is a rational pi of 3628800 / 1152480 = (1080/7^3) = pi school0pjs1 wrote on Dec 9, '10 The element of Time as a dimension may allow for a circumference in the universe that is a value of pi=3P where fast moving pure invisible energy slows down to transform into visible material in motion within a void of space. school0pjs1 wrote on Jan 22, '11 The Spencer Construction may represent an early "point in time". One step slower than x^3  2x^2 = 1. Very small. Then as the 10! circumference of time reaches out or grows to be a radius of 0.5 seconds or to average 576240 points of phi digits, the diagonals of the concentric square shrink back to being a diameter of one second long for its circumference. This makes the next 10! circumference of invisible dark energy. This dark energy compresses to penetrate the void which allows the invisible dark matter of chaos within the inscribed hexagon to also at the same point of forming a 10! circumference to enter the void and slow down to become visible matter in harmony with capacity in a combined singular spherical universe. 1) 10! circumference of time 2) 10! circumference of invisible dark energy from the concentric square 3) 10! circumference of invisible dark matter from the inscribed hexagon All three form a singular spherical multiuniverse of invisible time, invisible dark energy and invisible dark matter together. The Theory of Space 0/0 Dynamics school0pjs1 wrote on Mar 2, '11 Creative Pi (x y^7 z^2) / (x y^7 (k/3)) = 3P. Both the circumference and the diameter have elements raised to the seventh power. The mathematical speed of light raised to the seventh power would be 7.77x10^36 miles. This would make a universal radius of 3.885x10^36 miles. Such a radius of energy would shoot forth in all directions at 1/2 second of time from the timeless center spot when time was born. A 1/2 second of time 3.885x10^36 miles long would surround x^3  2x^2 = 1 in every direction. This would make a diameter of 7.77x10^36 miles/second long at 180 degrees. Now divide by 2 and a radius of 3.885x10^36 miles/SECOND is born. So the radius is now 1/2 second long and a full second long at the same time but only the 3.885x10^36 miles long physically. Both rational and irrational pi cooperate in space and time. school0pjs1 wrote on May 18, '11, edited on May 18, '11 Rational pi is 3P or C/d of the circumference while irrational pi is pi of the ngon perimeter. Rational pi is the curve that subtends irrational pi sides. school0pjs1 wrote on Jun 13, '11, edited on Jun 13, '11 The geometric Spencer Construction allows for hypothetical pi "H" to be developed. H in turn is the gravity between dark energy (the concentric square) and dark matter (the inscribed hexagon). As the circumferences of these three entities is being approached then a bond of gravity becomes stronger within the construction of mass. school0pjs1 wrote on Jun 14, '11, edited on Jun 14, '11 Likewise the speed of warp 1 to just under warp 10 would be generated by the advancing of digits of dark matter with a certain amount of energy wave distortion for cloaking purposes and the advancing of the digits of dark energy for hyper space drive. Between the two H pi digits maintain gravity in the star ship and pi time tolerances for top speed.. school0pjs1 wrote on Oct 26, '11, edited on Nov 7, '11 Phi^35 * Creative Pi forms a perfect circle for rational pi. C / d = pi: 64967633 / pi = phi^35 A calculator with a longer display shows the difference. phi^35 = 20633239.00000004846548813785357 Sorry. P.j.S school0pjs1 wrote on Dec 31, '11 In Your opinion which matters to me... ...is the simple algebra of Creative Pi for a rational solution for pi correct or not? Yes or no please?!. PJS standing by. P.j.S 
P JayS 
Sep 13, 2012, 06:52 AM
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#2

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
Creative Pi or rational pi forms a full and complete circle with the invisible point and the tangible physical point.
Transcendental Pi that begins with basic inscribed and circumscribed hexagons around a 3P circumference with d=1 travels in and out of time when the ngons avalanche through time. In other words the sides of the hexagons that become smaller as the pi approaches infinity do not form a closed circle in tangible space. Why is transcendental pi or irrational pi smaller than the circumference of creative pi? The circumference of rational pi is 3z. z = 360/7^3. z = k = P. 3z = 3.148688046... . The circle of 3z has an inscribed and circumscribed hexagon. As the sides of the hexagons increase toward infinity the circumscribed hexagon comes inside of the 3z circumference which equals a bigon of 38.111... sides. The value of 38 circumscribed sides is about the value of 3z at 3.14876077... . The circumscribed ngons of 39 sides form a smaller circumference in time at 3.14840548... . However the circumscribed ngon sides of irrational pi approaching infinity are always outside the pi circumference while the inscribed ngon sides are always inside the circumference of pi and P = pi/3 while P of 3z is 360/7^3. Pi/3 is smaller than 3z/3. The circumscribed hexagon is outside of time at 38 sides and lower amounts of sides. Therefore transcendental pi is inside and outside of pi = 3.1415... time for a circumference that is not closed and outside of rational pi at 38 sides as well. When irrational pi circumscribed sides increase from ngons from the pi circumference to 38 outside sides then the outside hexagon has become outside of 3z circumference time. In this manner transcendental pi is in and out of time. The avalanching irrational pi circumference is within 3z. But transcendental pi is within pi circumference with inscribed ngons and outside the 3z circumference as a circumscribed hexagon start (6 sides) to 38 sides. So the circumscribed ngon sides come inside the 3z circumference from which the inscribed and circumscribed hexagons get their start. The irrational pi circumference is inside the rational one at 39 sides for the circumscribed ngon. But the pi circumference is not complete. It reaches both inside and outside of 3z and time with circumscribed hexagon sides. To arrange a pi value for inside and outside sides see this pi calculator at this link: http://www.math.utah.edu/~alfeld/Archimedes/Archimedes.html P.j.S 
P JayS 
Sep 14, 2012, 07:36 AM
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#3

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
A bigon side (as i call it) is inside and outside of the curve of the 3z circumference. This occurs at 38.111 sides. At 38 bigon sides the perimeter equals the circumference. However the circumscribed ngon sides proceed from 38 sides to come inside of the 3z circumference.
Creative Pi = 3z is the rational pi circumference and transcendental pi which does not complete a full circle is inside and outside of rational pi or 3z time from its start (at 6 sides outside of 3z) to the ngon sides approaching infinity as the digits of pi continue on endlessly. 3z = pi at 38 bigon sides. circumscribed hexagon to 3z circumference ==> 38 bigon sides 3z = pi ==> 39 circumscribed sides to ngon circumscribed sides 3z > pi Both creative pi and transcendental pi are circles. But creative pi = 3z is the original tangible circumference in space and time with a diameter = 1. P.j.S . 
P JayS 
Sep 15, 2012, 02:42 AM
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#4

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
Currently I own Creative Pi and hold all the rights to it. It is my trade Mark found on the Internet called Creative Pi TM. This is my business trade mark publicly for around the world.
Everyone worldwide has been notified again. Thankyou! Creative Pi TM All Rights Reserved! Peter Jeffrey Spencer email: Creative.Pi.TM@gmail.com CThru Windows TM. 
P JayS 
Sep 29, 2012, 07:25 AM
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#5

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
Currently I own Creative Pi and hold all the rights to it. It is my trade Mark found on the Internet called Creative Pi TM. This is my business trade mark publicly for around the world. Everyone worldwide has been notified again. Thankyou! Creative Pi TM All Rights Reserved! Peter Jeffrey Spencer email: Creative.Pi.TM@gmail.com CThru Windows TM. 2x^2 = ? x = 3 a. (2x)^2 = 36 b. 2(x^2) = 18 c. a / b = 36 / 18 = 2 2 is 10% of 20 20 = 2(x^2) + (a/b) = 18 + (36/18) = 20 a square = 20 / 4 = 5 side a = 5 10% of 5 = 0.5 Note: this is the side of the object = 5 divided by the side of the subject = 10 side a = 5 / 10 = 0.5 area of the circumscribed square = (side a)^2 = (0.5)^2 = 0.25 area of the circle is x ®^2 = 3 * (d/2)^2 = 3 * 0.0625 = 0.1875 area of square / area of circle = 1.333... x = 4th root of dark energy = the radius of the circumscribed hexagon = 0.577350269... 2r = d (2x)^2 = (2r)^2 = d^2 = 1.333... d^2 * (x=3) = 4 4 times the area of the circle 0.1875 = 0.75 0.75 / (x=3) = 0.25 = r^2 = 0.25 r = sqrt 0.25 = 0.5 4 times the area of the circumscribed square is 4 * 0.25 = 1 area of square / area of circle = 4(0.25) / (4*0.1875) = 1.333... 1 / 0.75 = 1.333... 0.75 = area of the circle / (x=3) = 0.25 = r^2 r = sqrt 0.25 = 0.5 d = 2r = 1 with x = 3 This makes a unit circle with diameter of 1 and a circumscribed unit square with a side of 1 and a concentric square with a side of 0.75. The perimeter of the concentric square and the circumference of the circle (x=3) both equal 3. x = 1 36x / x^4 = 36 x = 7 10(36x / x^4) = P 36 / P = 34.3 36x (x=3) / xP = 34.3 10(108/34.3) = 1080/343 = 1080/7^3 = rational pi rational pi * r^2 = (1080/7^3) * 0.25 = 0.787172011 0.787172011 / 0.75 = P 3P = Creative Pi P * 0.75 = area of the unit circle = 0.787172011... 0.787172011... / r^2 = pi = xP = 3P = rational pi r = 0.5 
P JayS 
Sep 29, 2012, 02:46 PM
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#6

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
The Creative Pi Geometric Spencer Construction:
2x^2 = ? x = 3 a. (2x)^2 = 36 b. 2(x^2) = 18 c. a / b = 36 / 18 = 2 2 is 10% of 20 20 = 2(x^2) + (a/b) = 18 + (36/18) = 20 a square = 20 / 4 = 5 side a = 5 10% of 5 = 0.5 Note: this is the side of the object = 5 divided by the side of the subject = 10 side a = 5 / 10 = 0.5 area of the circumscribed square = (side a)^2 = (0.5)^2 = 0.25 area of the circle is x ®^2 = 3 * (d/2)^2 = 3 * 0.0625 = 0.1875 area of square / area of circle = 1.333... So 0.25 / 0.1875 = 1.333... note: to make these the sides of squares multiply by 4. 4 (0.25) / 4 (0.1875) = 1.333... 1 / 0.75 = 1.333... note: this is the length of the unit square divided by the length of the concentric square perimeter of the unit square 1 * 4 = 4 / perimeter of the concentric square and circumference of the circle 1 * x = 3 equals 1.333... The area of the circle = one side of the concentric square = 0.75 The area of the circle * P = 0.787172011... 0.787172011 / r^2 (0.25) = 10! / 1152480 Note: P/10 = 36x / x^4 with x=7 and (C = 10!) = (x y^7 z^2) = 3628800. x=4, y=7 and z=360/7^3. z = P. 10! / z = perimeter of the concentric square = 3457440 perimeter of concentric square = circumference of the circle / z = 3457440 3457440 / x = 1152480, x = 3 The inscribed hexagon has the same perimeter as the concentric square. so 3457440 / 6 = one side of the hexagon which = the radius = 576240 So the diameter of the circle in question is 2r = 1152480. So rational pi is the circumference is 3628800 / by the diameter 1152480 = 1080/7^3 x^3 * 1.333... = 457.333... 360 / 457.333 = area of unit circle = 0.787172011... 0.787172011... / r^2 = 10! / 1152480 radius of the unit circle = 0.5 Creative Pi is pi = 3P = 1080 / 7^3 
P JayS 
Sep 30, 2012, 06:55 AM
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#7

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
Creative Pi and Discovering the 10! Circumference:
x^4 / x^3 = 1/1 = 3/3 = 81 / 27 = 3 = x x^4 + x^3 = 108 81 + 27 = 108 108 / x = 36 36x / x^4 = 36 x=1 36x / x^4 = P / 10 x=7 36x * 10 = P * x^4 360x = P (x^4) 360 * 7 = P (x^4) 2520 / x = P (x^3) 360 = P (7^3) 360 / 7^3 = P = z 10! / z^2 = 4 (x^7) 10! / z = 4 (x^7) z 3457440 = 3457440 the perimeter of the concentric square and the inscribed hexagon 3457440 / 6 = 576280 = the radius 10! / 2r = 1080 / 7^3 x=3 10! / x P = 1152480 = 2r = d C = 3dP 10! = x d P 10! = 3d * P (perimeter of the inscribed hexagon) * P 10! = 3 (1152480) * (360 / 7^3) 10! = 3628800 C / d = pi 3628800 / 1152480 = 1080 / 7^3 C = 10! d = 1 in pi circumference C = 3dP C = 3 (1) (360 / 7^3) pi circumference = 1080 / 7^3 x = 4, y = 7 and z = 360 / 7^3 The concentric square = 4 (y^7) z The insceribed hexagon = 10! / P The pi circumference = 10! / z All three perimeters = 3457440 10! / z = 4 (y^7) z C = 10! = (x y^7 z^2) C = 3dP (x y^7 z^2) / 3P = d x y^7 z / 3 = d Note: z = P so z^2 / P = z 3457440 / 3 = d = 1152480 3628800 / 1152480 = 3P = pi 3 (360 / 7^3) = pi 1080 / 7^3 = pi pi = 3P P = pi / 3 P = 3z / 3 P = 360 / 7^3 = z Creative Pi = 1080 / 7^3 
P JayS 
Jan 10, 2013, 02:20 PM
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#8

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
At first the circumscribed hexagon is 6 sides around the outside of a circumference with a radius of 1. An inscribed hexagon also meets inside the circumference with a radius of 1.
As the sides of the two polygons are increased they meet at a point on the perimeter of the sides that is subtended by the circumference. The circumscribed side of the hexagon does not stay outside of the circumference. It comes inside to meet the inscribed hexagon side at the apothem point that is maximum height but not reaching the circumference. At 38 circumscribed sides running outside of the circumference pi perimeter is almost 3P circumference value. Next at 39 bigon sides running inside and outside of the circumference the pi perimeter has come partially inside the 3P circumference on its way to meet up with the inscribed ngon at the apothem point. This group of apothem points comprised of the once circumscribed sides of the hexagon meeting together with the height of the inscribed hexagon ngon apothems reaches a pi perimeter of 3.1415926... which is shy of the 3P = 1080/7^3 circumference. The pi perimeter made up of both hexagon sides together completely inside the circumference of the circle is subtended by the arc of the 3P circumference. The two end points of each of the ngon sides are on the circumference while the two sides meeting at the apothem point of the inscribed hexagon in the middle of each side make up the pi perimeter. The apothem of the inscribed hexagon ngon side never reaches the full radius of the circumference. Its ngon side is always shorter than the arc of the circle that subtends the ngon side. Thus the digits of pi go on endlessly per counting side of the ngon inside of the circumference at each apothem point per side. Why does the circumscribed side come inside the circumference? Answer: The two end points of the circumscribed side reach the circumference. This brings the midpoint of the ngon side inside of the circumference to meet up with the inscribed ngon side which both end points of that side are on the circumference as well. The midpoints of both ngon sides are at the end of the apothem of the inscribed ngon forming pi perimeter which is barely less than the radius = 1 of the circle. P.j.S 
P JayS 
Jan 17, 2013, 07:46 AM
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#9

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
The Perimeter of the 6 Sided Circumscribed Hexagon: Public Notice as follows:
x = (1, 3) x^2 = 1 * 3 = 3; Note: 2 of different (x) each; rendering (1 and 3) as x^2. x = sqrt 3 2x = 2 * (sqrt 3) = 2 sqrt 3, further: 2x^2 = 48; $ + 8 = $12.00. ! + 2 = 3. A Three Fold Chord of Love ... . No injustices of the Sales Goods; please. x = 2 sqrt 3 2x^2 = ( 4, 36); (x = 1, x = 3); 4 + 36 = 40, The Subject of the Room of Objectivity is 17. 40  17 = 23 = 5.0. = 999 or x^3 with 666 in the room of objectivity 5555. 3 root 999 = 9.996665555...5... . P = The 6 Headed Beast & the 4 Sided Square = 6 + 4 = the Blower of the 10th Horn! . Note: (individual bragging rights concerning with their own accomplishments as well). That is what I/i think about it. How about you? The Well is a little less Grounded now perhaps and the merky waters of life a little clearer now. Am I AM sure of it. Peter J. Spencer ®: Pp : I/i"n' the Language of Love. . Amen. Amen 
P JayS 
Jan 18, 2013, 05:24 AM
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#10

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
Circles and Hexagons
Pi ran the course. It did its job right.. It kept people puzzling. Long into the night. The inscribed hexagon wondered whether small lines was the way. To gain the circumference of the circle some very long lasting day. But now we do know that the arc curves supreme. The lines were real close but yet just only a gleam. Clever Pi being 3.141... comes up a little bit short. It's precisely 3.148... is my humble & modest retort. Peter J. Spencer 
P JayS 
Jan 18, 2013, 05:34 AM
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#11

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
Life's Like That
Everywhere you look there is something there to see. Most of it grows around us like an orange in a tree. You and me we fumble or we bumble like a bee. Yet on the merrygoround of life we just yearn for harmony. We notice a double rainbow there, it is beauty in the sky. A full moon comes out at night, we look and wonder, why? Sunshine in the eyes of an enfant may make her want to cry. Even when our telephone "rings" we have to say goodbye! Life is very odd you know a curve beyond belief. A loop to loop roller coaster ride for childlike relief. After going 'round awhile we tremble like a leaf. And sum it all up this way with an expression of "Good Grief!" Pete 
P JayS 
Jan 18, 2013, 08:32 AM
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#12

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
The After Math
"Don't throw any of that odd math away for fear that your garbage can may accrue but your bank account may not!". For your consideration: Creative Pi the Legal Original Mathematics of Peter Jeffrey Spence®™... Waste not want not! P.j.S standing by Lord. Our Creator of Originality knows why. Amen 
P JayS 
Jan 19, 2013, 12:33 AM
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#13

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
If Pi could Fly
If pi could fly then off to the sky. Don't ask me why or if its dry. His digits would grasp everything in his clasp. In a box with a hasp be his compass and rasp. A circle he'd make. A rainbow like cake. Filed smooth for the take. For everyone's sake. You know he's well rounded. Rational and well bounded. Remember well founded. But not flying, well grounded. Peter J. Spencer Thankyou for the sincere interest you have shown in learning about the Mathematical Number Values of Pi! Amen 
P JayS 
Mar 14, 2013, 10:09 PM
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#14

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
Thursday was Pi Day. Is there anything new that could be said about pi? Yes.
The radius of the circle is 1. The circumscribed hexagon goes from a side of (2 sqrt 3) / 6 down to a ngon point of 1 on the circumference. The inscribed hexagon goes from a side of 3 / 6 to an ngon point of 1 at the circumference using calculus for both sides. All there is a single point 1 away from the center. To make a semicircle between 2 and 0 on the x axis with the point due north from the center would result in an arc of irrational pi value. Now to take the line from the center to the point 1 away at due north and make that the diameter of another circle would be to create a circle with a radius of 0.5 or a circumference of rational pi value and with a diameter of 1. The mistake is to think that all circles are the same. They are not. Part of the arc of the semicircle is P = pi/3 but part of the arc of the inner circumference is P = 360/7^3 or 3z/3 where P = z. Both circles are not the same value. Both irrational and rational pi exist at the same time. The geometry proves this. To say that both semicircle and inner circumference are irrational pi is false. Likewise to say that both inner circumference and external semicircle are Creative Pi is false as well. I have proved this thoroughly. Using Archimedes method of circumscribed and inscribed hexagons only produces a common point that is 1 away from the center on the y axis. A line from the center to the point makes the diameter of a circumference that is rational pi value within a semicircle of irrational pi value. A line tangent to the southern point of the inner circumference at the center point will create the diameter of irrational pi across the semicircle along the x axis. I am not professional in my speech about the geometry but one can draw the semicircle and inner circumference using both the center point and the point due north from Archimedes method. There is no circle between the two ngons. The value of the two ngons works out to 1 in the calculus. But the inner circumference uses Algebra and a radius of 0.5 to calculate. Both pi exist at the same time. To say that the semicircle has a radius of 1 is fine. This makes a projected full circle of irrational 2pi. But with this circle is two inner circumferences of rational pi value tangent to the center point and each other. It is inescapable. It is time to recognize and acknowledge that i am right. The semicircle of irrational pi or Transcendental Pi has to do with time. The circumference of rational pi or Creative Pi has to do with the tangible visible point that grows within the spiral of 1/phi to the zero dimension and beyond along the z axis. To say that "a" circle has a diameter of 2 and 1 at the same time is to talk about not the same circle but two distinct circles. For example the semicircle of pi value has a diameter of 2. But the circumference of pi value has a diameter of 1 at the same time. To say that a semicircle has a valued diameter of 1 is to talk about rational pi and the semicircle is not pi value then but 3z/2. The fact is that Transcendental Pi does not complete the circle. The circumscribed ngon side is always a little longer than the proportional arc and the inscribed ngon side is always a little shorter than the subtending arc. Thus the circle is not to be thought of as the average of these two figures although they are not exact true pi value at the same time. The porojected semicircle value is irrational pi It should be observed though the the rational circumference with a diameter of 1 is a perectly closed and complete circle within the open semicircle. Two semicircles do not make a closed circle although each semi circle has a rational circumference within it. Once again a semi circle is made from the x axis with 0 and 2 value on each end and a value of 1 for the point at the top end of the positive y axis (that originates from the center or mid point of the x axis) where the two ngons meet by means of the calculus. To rotate the ngon point at the top end of the y axis in either direction from the midpoint of the x axis is to create a semicircle of irrational pi value with a diameter of 2 and a circumference of rational pi value with a diameter of 1 at the same time. Yours Truly, Peter Jeffrey Spencer 
P JayS 
Mar 25, 2013, 08:09 AM
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#15

DemiGod Group: Basic Member Posts: 588 Joined: Apr 04, 2012 Member No.: 34146 
Considering Archimedes method for discovering pi we add a circumscribed hexagon to the circumference. This is outside the circumference. In all honesty another outside circle can be made tangent to the outside of the circumscribed hexagon.
What then? All we have is another inscribed circle relationship with a hexagon. But what do we observe? That the simple line (circumscribed square around the original circumference) has grown in size. We can imagine that the growth of the simple line from the start of an invisible point to a tangible one would be tremendous growth! Causing the circumscribed hexagon to become as an ngon of infinite sides only causes transcendental time to the point of a radius of 1 for the inscribed and circumscribed hexagons since they never reach the point of the tangible circumference. Time therefore has much more to offer than just being a linear measurement of distance. Parsecs and dimensions to name a couple of possible realities of time and quite possibly other considerations beyond our scope of understanding presently. Time is the spiritual body of the universe with everything in relation to everything else. P.j.S . 
LoFi Version  Time is now: 19th November 2017  12:35 AM 