Prove that P = a ± b?, Singularity towards Artificial intelligence AI... 
Prove that P = a ± b?, Singularity towards Artificial intelligence AI... 
omegapoint 
Sep 14, 2010, 03:30 PM
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#1

Newbie Group: Basic Member Posts: 24 Joined: Sep 14, 2010 Member No.: 33085 
Singularity towards artificial intelligent AI and a model for the expansion of
the universe: Prove that P = a ± b ? 
Hey Hey 
Sep 16, 2010, 12:10 AM
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#2

Supreme God Group: Basic Member Posts: 7767 Joined: Dec 31, 2003 Member No.: 845 
I'm getting a headache again ...

Hey Hey 
Sep 17, 2010, 04:26 PM
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#3

Supreme God Group: Basic Member Posts: 7767 Joined: Dec 31, 2003 Member No.: 845 
Migraine ...

Trip like I do 
Sep 17, 2010, 07:45 PM
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#4

Supreme God Group: Basic Member Posts: 5157 Joined: Aug 11, 2004 From: Earth^2 Member No.: 3202 
lol.... it's like the voynich manuscript.... slightly familiar, yet completely unintelligible

Hey Hey 
Sep 18, 2010, 08:06 PM
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#5

Supreme God Group: Basic Member Posts: 7767 Joined: Dec 31, 2003 Member No.: 845 
Need pressure shunt fitting to head ...

Hey Hey 
Sep 22, 2010, 05:40 PM
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#6

Supreme God Group: Basic Member Posts: 7767 Joined: Dec 31, 2003 Member No.: 845 
So nothing is what it's always been, then?

omegapoint 
Sep 23, 2010, 12:10 PM
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#7

Newbie Group: Basic Member Posts: 24 Joined: Sep 14, 2010 Member No.: 33085 

Hey Hey 
Sep 23, 2010, 03:23 PM
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#8

Supreme God Group: Basic Member Posts: 7767 Joined: Dec 31, 2003 Member No.: 845 
6.
That was an arbitrary number. 54. That was another. 
Hey Hey 
Sep 25, 2010, 03:30 PM
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#9

Supreme God Group: Basic Member Posts: 7767 Joined: Dec 31, 2003 Member No.: 845 
Time for the amber nectar ...

omegapoint 
Sep 26, 2010, 01:15 PM
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#10

Newbie Group: Basic Member Posts: 24 Joined: Sep 14, 2010 Member No.: 33085 
Ah what an Australian phrase!

Hey Hey 
Sep 26, 2010, 02:15 PM
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#11

Supreme God Group: Basic Member Posts: 7767 Joined: Dec 31, 2003 Member No.: 845 

omegapoint 
Sep 26, 2010, 02:31 PM
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#12

Newbie Group: Basic Member Posts: 24 Joined: Sep 14, 2010 Member No.: 33085 

PJS 
Sep 29, 2010, 02:23 PM
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#13

Awakening Group: Basic Member Posts: 216 Joined: Aug 17, 2006 Member No.: 5507 
2916  54b' + c = 0.
54b = c + 2916 b = (c + 2916)/54 b = (c/54)  54 b + 54 = c/54 b/54  1 = c c  (b/54) = 1 got this far now... c = (b/54) 1 Simply enter a value for b and find c. For example b=54 then c=2 or b=54 then c=0. I hope that this helps. P.j.S 
Hey Hey 
Sep 30, 2010, 05:59 PM
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#14

Supreme God Group: Basic Member Posts: 7767 Joined: Dec 31, 2003 Member No.: 845 
I'm not a celebrity, get me out of here!

GodConsciousness 
Sep 30, 2010, 06:49 PM
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#15

DemiGod Group: Admin Posts: 918 Joined: Sep 19, 2006 Member No.: 5683 
I like you guys but you're crazy!

omegapoint 
Oct 03, 2010, 02:57 PM
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#16

Newbie Group: Basic Member Posts: 24 Joined: Sep 14, 2010 Member No.: 33085 

Hey Hey 
Oct 03, 2010, 09:38 PM
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#17

Supreme God Group: Basic Member Posts: 7767 Joined: Dec 31, 2003 Member No.: 845 
omegapoint, you're Count Arthur Strong aren't you? http://www.youtube.com/watch?v=08QNfF78jb4&feature=related

omegapoint 
Oct 06, 2010, 02:18 PM
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#18

Newbie Group: Basic Member Posts: 24 Joined: Sep 14, 2010 Member No.: 33085 
What's next?

Trip like I do 
Oct 06, 2010, 05:06 PM
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#19

Supreme God Group: Basic Member Posts: 5157 Joined: Aug 11, 2004 From: Earth^2 Member No.: 3202 
robert the bruce is that you.... c'mon now fess up!

omegapoint 
Oct 10, 2010, 03:27 PM
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#20

Newbie Group: Basic Member Posts: 24 Joined: Sep 14, 2010 Member No.: 33085 
This post is edited to enhance readability.
Prove that P = a ± b? ABSTRACT. The aim of this proof is to create a system that can solve itself without human intervention which encompasses an AI choice mechanism, a self awareness system and a model for an expanding universe. The AI choice mechanism and the self awareness system is after the model must have been created. Basic number theory shows that it is possible to combine any number by the addition of two other suitable numbers.Still in general, it is not impossible to prove that P = a ± b because the said "Proof P = a ± b" support the infinite list of possible numbers which when added together sum to any given number. The proof: Prove that P = a ± b? using a formula. (Optional: when P ≠ a ± b at a point to infinity i.e. when P = 1 to both positive infinity and negative infinity).Given that P is arbitrary number where a and b are entities of the arbitrary number. The knowledge base (encapsulated, appropriate for public use): Prove that A = B when A ≠ B at a point to infinity i.e. a point to both positive infinity and negative infinity. Note: Both the Proof and the knowledge base amount to the same thing. Firstly, in order establish that P ≠ a ± b. Let's consider that a = P where P is arbitrary number. a + b = P implies a  P = b. a  b = P implies a  P = +b. Thereby ±b can equally occupy a given space. And If and only if b = b when b = 0. Then the logic demands that a + b = a  b. Such that P = a(+b  b ). Therefore for every negative b, there is a positive b where P is arbitrary number. So that P = a(0) Also that P = 0 Thus P ≠ P and P ≠ a ± b end. Note:If we can generate a proof that P = a ± b.Then P = a ± b can resurrect from here. Since 0 = 1 in quantum mechanics and 0 = 1 is infinite with the Proof P = a ± b. Therefore P = a(1) and P = a. Since a = P when P = 1. Then P = 1. Thus P = P and P = a ± b end. However, P = P with the proof P = a ± b where 0 = 1 at a certain point of the application. Alternatively, P = P if 0 = 1 like in quantum mechanics but it has a limit. Though the proof P = a ± b has no limit.So the proof P = a ± b can aid "0 = 1" in quantum mechanics! Now. From the proof P = a ± b which implies a  P = ±b. Let's consider that: a  P = ±b. To the extent that: a  P = 0( + b  b ). Such that a  P = 0(0). REASON {THE ENTANGLEMENT}: Importantly, both the proof P = a ± b and the knowledge base simultaneously yielded equal variables until b = 0. When b = 0, the proof P = a ± b yielded b and the knowledge base yielded b respectively. Therefore +b and b can coexist but logic demands that b = b when b = 0. Thus everything amount to zero (0). Also. From the Knowledge base: Given that B is the existence of A. If A ≠ B.Then there is no evidence to show that A and B exist to an extent that B is not visible at this point. Therefore, A and B are consider to be nonexistent illusion when A ≠ B. If A = B.Then there is an evidence to show that A once existed and B exist to an extent that B is visible at this point. Thus B is the only evidence that A once existed. ILLUSTRATION: Assuming space system is the domain that hold each group of orientation in space according to the concept. While movement (m) is movement of an object (P) in space from an infinite origin. Now, let's assume this orientation in space, ( b, 0 , b ) or ( b, 0, b ) is in relation with the expansion of the universe.Such that we have the following result at each movement (m) ranging from a negative infinity to a positive infinity passing through the origin 0.i.e From an infinite origin... The Proof P = a ± b at a certain system yields this where system here is considered to be the difference between P and b from a + b = P: At this stage before the turning point P ≠ a ± b or A ≠ B. When movement (m) = 5 contraction of the universe is ( 3.0, 0, 3.0 ) When movement (m) = 4 contraction of the universe is ( 2.5, 0, 2.5 ) When movement (m) = 3 contraction of the universe is ( 2.0, 0, 2.0 ) When movement (m) = 2 contraction of the universe is ( 1.5, 0, 1.5 ) When movement (m) = 1 contraction of the universe is ( 1.0, 0, 1.0 ) When movement (m) = 0 contraction of the universe is ( 0.5, 0, 0.5 ) When movement (m) = 1 size of the universe is ( 0, 0, 0 ) Thereby there is a turning here and a turning point can be determined. Note: P is consider to loose its form when movement(m) ≤ 1 i.e when P ≤ 1.Thereby b is not visible until when P ≥ 2. At this stage after the turning point P = a ± b or A = B when A ≠ B. When movement (m) = 2 expansion of the universe is ( 0.5, 0, 0.5 ) When movement (m) = 3 expansion of the universe is ( 1.0, 0, 1.0 ) When movement (m) = 4 expansion of the universe is ( 1.5, 0, 1.5 ) When movement (m) = 5 expansion of the universe is ( 2.0, 0, 2.0 ) When movement (m) = 6 expansion of the universe is ( 2.5, 0, 2.5 ) When movement (m) = 7 expansion of the universe is ( 3.0, 0, 3.0 ) This continue to infinity... Thus: Let consider that when contraction of the universe is in DISORDER or CHAOS ( b, 0, b ) is less than or equal to ( 0.5, 0, 0.5 ). Such that there is a turning point when expansion of the universe is ( 0, 0, 0 ). So that there is a turning when expansion of the universe is in ORDER ( b, 0, b ) is greater than or equal to ( 0.5, 0, 0.5 ). Therefore the turning point which is the point of the big bang could be determine when there is a sufficient reason. This tells us that DISORDER beget ORDER.i.e DISORDER = ORDER. Therefore, the universe can be said to be homogeneous in this manner for every arbitrary number as it is expanding from when b = 0 to infinity, when b ≠ 0. As a result, lightest element i.e. hydrogen atom “lifted” in a linear superpositioning would be an appropriate tool for the model. All this explanation is in relation with what quantum entanglement is all about. What we're doing is also to generate something out of nothing where nothing is quantified as space. Wisdom is needed to understand all that i have written. Wisdom is the right application of knowledge. It's a math for singularity. Cheers! 
omegapoint 
Dec 23, 2010, 09:49 AM
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#21

Newbie Group: Basic Member Posts: 24 Joined: Sep 14, 2010 Member No.: 33085 
Now the model is ready and here is the link; Global news via: www.gliict.com

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